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lawyer [7]
3 years ago
7

Help find the perimeter and area

Mathematics
2 answers:
Firlakuza [10]3 years ago
5 0

Answer:

Perimeter = 8.4×4 = 33.6 meters

Area = 8.4^2 = 70.56 square meters

hichkok12 [17]3 years ago
4 0

Answer:

P =33.6 m

A = 70.56 m^2

Step-by-step explanation:

The perimeter of a square is given by

P =4s = 4(8.4) =33.6 m

The area of a square is given by

A = s^2 = (8.4) ^2 =70.56 m^2

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To understand the algebra, go through the following equations below:

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Part B

  • First equation : y = n^{2} + n
  • second equation: y = n + (n*n)

<h3>Meaning of algebra</h3>

Algebra is defined as a branch of mathematics that deals with variables, symbols and finding of these unknown using arithmetic operation such as ( +,  -,  *,  ÷ )

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2 years ago
Help me please I beg
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As far as I understand A)

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3 years ago
What is the answer for 4x + 2y = 12
sesenic [268]

Answer:

(1,4), (2,2) (3,0)

Step-by-step explanation:

adjust the equation so that the y is isolated so subtract 4 x

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In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

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3 years ago
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