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Sedaia [141]
3 years ago
8

Consider any positive four-digit integer that has all of its digits distinct and none equal to zero. What is the largest possibl

e difference between such an integer and any integer that results from rearranging its digits
Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Answer:

<h2>Check the explanation.</h2>

Step-by-step explanation:

The highest four digit number is 9999 and lowest 4 digit number is 1000. The difference between them is (9999 - 1000) = 8999.

8999 cannot be difference according to the question, as here all the digits should be distinct rather than 0.

The difference between the 9 and 1 is 8, which is the highest difference among the unit digits rather than 0.

The 2nd lowest number after 9 is 8 and the 2nd highest unit digit after 1 is 2.

(8 - 2) = 6.

The difference will be highest if difference is calculated between the highest and lowest number.

With the 4 digits, 9, 8, 2, 1 the lowest number is 1289 and the highest number is 9821.

The difference is (9821 - 1289) = 8532.

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Binomial (x - 6) and trinomial (-2x2 + x + 9) are the factors of which of the
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Answer:

Option (3)

Step-by-step explanation:

If binomial (x - 6) and trinomial (-2x² + x + 9) are the factors of a polynomial then their multiplication will be equal to the polynomial.

(x - 6)(-2x² + x + 9) = x(-2x² + x + 9) - 6(-2x² + x + 9)

                              = -2x³ + x² + 9x + 12x² - 6x - 54

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Answer:

  d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

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  (6d +1)^2 = 1 . . . . . . . . . .subtract 12

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Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

  f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

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