Answer:
Equation of line shown in the graph is : x= - 2
Step-by-step explanation:
Given,
a line passing through two points ( -2,2) and ( -2,-3).
We need to use two pint line equation:
y - y1 = (y2 - y1 / x2 - x1 ) (x - x1 )
Here , x1 = -2 ,x2 = -2 , y1 = 2 and y2 = -3
So we can plug corresponding values in the line equation.
We get: y - 2 = {(-3 - 2) / ( -2 - (-2))} (x - (-2))
y - 2 = (-5 /0 ) (x + 2)
0 * (y - 2) = -5 (x+2)
0 = -5x - 10
10 = -5x
x = -10/5 = -2
Hence x= -2 is the equation of line shown in the graph.
I took the liberty of finding for the complete question.
And here I believe that the problem asks for the half life of Curium. Assuming
that the radioactive decay of Curium is of 1st order, therefore the
rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
It gets repetitive really fast. The second verse is the same as the first. The result is ...
The correct answer is 15:25
Answer:
Option D. 
Step-by-step explanation:
we have
we know that
The denominator cannot be equal to zero
therefore
To find the equation of the vertical asymptote equate the denominator to zero
so
-----> equation of the vertical asymptote
