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2 years ago

Use long division to find a repeated decimal equivalency for the fraction 6/9

Mathematics

2 answers:

Sliva [168]2 years ago

4 0

It gets repetitive really fast. The second verse is the same as the first. The result is ...

$\dfrac{6}{9}=0.\overline{6}$

IceJOKER [234]2 years ago

4 0

6/9 is your answer :)

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(PLESE HELP) Factor the following expression. Simplify your answer.

mars1129 [50]

The factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

$5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$

Since $(p + 2)^{\frac{1}{3} }$ is common, we factor it out. So, we have

$(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2} + 4)$

Expanding the bracket, we have

$(p + 2)^{\frac{2}{3} } (5p(p^{2} + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

So, the factor of the expression $5p(p + 2)^{\frac{2}{3} } + 4(p + 2)^{\frac{1}{3} }$ is $(p + 2)^{\frac{2}{3} } (5p^{3} + 10p^{2} + 20p + 4)$

Learn more about factorization here:

brainly.com/question/11579257

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BaLLatris [955]

The way your problem is set it should be simplified to this....4x + 55

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A sample of 184 light bulbs contained 6 defective bulbs, at this rate ,how many defective bulbs would you expect to find in a sa

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3 years ago