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Romashka-Z-Leto [24]
3 years ago
6

The value of the varriable which satisfies the equation is called the _______ of the equation​

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:

solution

Step-by-step explanation:

solution is the answer

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A caterpillar crawling in a straight line across a coordinate plane starts at point (-3,
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9514 1404 393

Answer:

  15

Step-by-step explanation:

In vector form, the equation of point p on the line can be written as ...

  p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t

  p = (-3, -4) +t(28, 42)

  p = (-3, -4) +14t(2, 3)

where t takes on any value between 0 and 1.

If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.

There are 15 values that n can have in the allowed range.

The caterpillar touches 15 points with integer coordinates.

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2 years ago
5/6 x 3/20 as a fraction
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Step-by-step explanation:

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3 years ago
In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?  ANS
loris [4]

Answer:

The number of musicians in the school is 3 times the number of athletes

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Which expression represents the following calculation?
mrs_skeptik [129]

Answer:

7.4 x (87-24)

Step-by-step explanation:

The translation is that you multiply the difference of two numbers. So you must get the difference first, that's why you put parenthesis around 87-24. Your answers are sideways and are hard to read, so I'll just give you the correct answer without the answer choice.

5 0
3 years ago
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Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re
kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read 13\frac{3}{4} pages in \frac{1}{4} of an hour.

Therefore, pages read by Zander in 1 hour = \frac{\text{Total pages read}}{\text{Total time taken}}

= \frac{13\frac{3}{4}}{\frac{1}{4}}

= \frac{55}{4}\times \frac{4}{1}

= 55 pages per hour

Sydney read 43\frac{1}{3} pages in \frac{2}{3} of an hours.

Pages read by Sydney in 1 hour = \frac{43\frac{1}{3}}{\frac{2}{3} }

= \frac{130}{3}\times \frac{3}{2}

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0
3 years ago
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