3 years ago

Application of linear equation in two variable in real life

1 answer:

Ivan3 years ago

6 0

We can compare the two units or object performances by that.... even in the case of magnitude lower than zero....

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tester [92]

Answer:

4.465 × $10^{-2}$

Step-by-step explanation:

235.000 × 0.00019

2.35 × 10² × 1.9 × $10^{-4}$

2.35 × 1.9 × 10² × $10^{-4}$

4.465 × $10^{2+(-4)}$

4.465 × $10^{2-4}$

4.465 × $10^{-2}$

7 0

3 years ago

kenny6666 [7]

The line and parabola intersect at about x=-2 and x=1.5 so the solution is A. x = -2

8 0

3 years ago

Sergeeva-Olga [200]

Answer:

Vertex: (1/2, 16)

Zeros: t = − 1 /2, 3/2

Step-by-step explanation:

4 0

2 years ago

Sedbober [7]

V=hpir^2
d/2=r
5/2/2.5

h=7
V=7pi2.5^2
v=7pi6.25
V=43.75pi
aprox pi=3.141592
V=137.44465

V=43.75pi ft^3 or aprox 137.44465 ft^3

7 0

3 years ago

Lelu [443]

i can help, but you need to write the whole question..

7 0

2 years ago