Application of linear equation in two variable in real life

Mathematics

1 answer:

Ivan3 years ago

6 0

We can compare the two units or object performances by that.... even in the case of magnitude lower than zero....

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I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
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\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
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\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$

7 0

3 years ago

You’re given two side lengths of 3 centimeters and 5 centimeters. Which measurement can you use for the length of the third side

mrs_skeptik [129]

Answer:

You could use a measurement of 4 centimeters.

The valid range is 2 < x < 8 cms.

Step-by-step explanation:

The third side must either be less than 3+5, that is less than 8 cms and it must be greater than (5-3) = 2 cms. If it is any other length we could not construct a triangle.

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3 years ago

Larry borrows $1300 at 5% simple interest per month. When Larry pays the loan back 3 years later, what is the total amount that

Dafna11 [192]

I think that it’s 3640

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sp2606 [1]

Answer:

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