<h3>Given:</h3>
<h3>To find:</h3>
- The approximate volume of the given sphere.
<h3>
Solution:</h3>

Let's substitute the values according to the formula.
Let's solve!


Now, well have to round off to the nearest hundredth.

<u>Hence,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>sphere</u><u> </u><u>is</u><u> </u><u>523.6</u><u> </u><u>cubic</u><u> </u><u>units</u><u>.</u>
Note: If your using π as π you'll get this answer.
Answer:
woof
Step-by-step explanation:
<span>a) In which quadrant of the coordinate plane is point A located? Quadrant I
b) what are the coordinates of translated point A'? in which quadrant of the coordinate plane is point A located? (5,-3) ; Quadrant IV
c) what are the coordinates of reflected point A''? in in which quadrant of the coordinate plane is point A located? (-5,-3) ; Quadrant III
Pls. see attachment. </span>



now, with that template in mind, let's see
3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3
vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then
and shifted down by 3, do D = -3