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Debora [2.8K]
2 years ago
5

Consider the system and find the eigenvalues and the eigenvectors

Mathematics
1 answer:
geniusboy [140]2 years ago
8 0

Eigenvalues are the special set of scalar values which is associated with the set of linear equations in matrix equations.

<h3>What are Eigenvalues?</h3>

Your information is incomplete. Therefore, an overview will be given. An eigenvector of a linear transformation is a nonzero vector that changes by a scalar factor when the linear transformation is applied to it.

The eigenvectors of matrix A are those vectors X for which multiplication by A will result in a vector in thesame direction or opposite direction to X.

Since the zero vector 0 has no direction, 0 is never allowed to be an eigenvector.

Learn more about eigenvalues on:

brainly.com/question/15423383

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Viktor [21]

Answer:

36?

Step-by-step explanation:

split in two, triangle 6x6=36/2=18, rectangle 6x3=18, whole 18+18=36 your answer is 36

3 0
2 years ago
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denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ c =  \sqrt{ {a}^{2} +  {b}^{2}  }

dc =  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\  cf = 1 \\ fe =  \sqrt{ {4}^{2}  +  {2}^{2} }  =  \sqrt{20}  \\ de =  \sqrt{ {1}^{2} +  {4}^{2}  }  =  \sqrt{17}  \\  \sqrt{10}  + 1 +  \sqrt{20}  +  \sqrt{17}  = 12.76

7 0
3 years ago
I need help with my math problem #6
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3 years ago
1. Find the Length of Line AD A(6, 2) D(-3, -2)
densk [106]

Answer:

5

Step-by-step explanation:

\sqrt{(2-(-2))^{2}  + (6-(-3))^2}

=\sqrt{4^{2}  + 3^{2} } \\

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2 years ago
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lubasha [3.4K]

x=0 or x=4

just factorize basically

cancels the x’s so it’d be 3x-12=0 and from that x=4

3 0
3 years ago
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