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3 years ago

If BC = CD and AB = 23, what is BD?

Mathematics

1 answer:

True [87]3 years ago

7 0

BD = 46

Explanation:
BC = CD and AC is used for both triangles so AD MUST = AB.
If AB = 23, then AD = 23.
BD = AB + AB
BD = 23 + 23
BD = 46

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Step-by-step explanation:

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we can substitute the value of sec(θ) in this equation:

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b) since right triangle is mentioned in the question. We can use:

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length of the adjacent side = 1
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we can find the third side using the Pythagoras theorem.

$(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2$

$(52)^2=(1)^2+(\text{opp})^2$

$\text{opp}=\sqrt{(52)^2-1}$

$\text{opp}=\sqrt{2703}$

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we can find the sin(θ) using this side:

$\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}$

$\sin{\theta} = \dfrac{\sqrt{2703}}{52}}$

and since $\csc{\theta} = \dfrac{1}{\sin{\theta}}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

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