X^2+8x-3>-19 | +19
x^2+8x+16>0
x^2+4x+4x+16>0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
this is true cause (X+4)^2 >0 cause X+4>0
I'm not completely sure but I think it is -5x.
A square + B square = C square
The figure shows two intersecting chord, thus this simply can be solved using the Intersecting Chord Theorem, which states that "<span>When two chords intersect each other inside a circle, the products of their segments are equal."
Thus,
(15mx2m=5mxn)
n=6m</span>
8x-4=2x-3
One solution was found :
x = 1/6 = 0.167
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
8*x-4-(2*x-3)=0
Step by step solution :
Step 1 :
Solving a Single Variable Equation :
1.1 Solve : 6x-1 = 0
Add 1 to both sides of the equation :
6x = 1
Divide both sides of the equation by 6:
x = 1/6 = 0.167
One solution was found :
x = 1/6 = 0.167
i am not solving for x i am solving for you lol!!!
