Specific heat of Aluminium is 0.89 g/J
Explanation:
Step 1 :
Specific heat of a substance is the energy absorbed by a substance of unit mass when its temperature increases by one degree.
Energy Absorbed = Specific Heat * Mass of the substance * Temperature Difference
Step 2 :
It is given that 120 g sample absorbs 9612 J energy when the temperature increases from 298K to 388K.
Temperature Difference = 388 K - 298 K = 90 K
Step 3:
Specific Heat = (Energy Absorbed) ÷ (Mass of the substance * Temperature Difference)
Specific Heat = 9612 ÷ (120 * 90) = 0.89 grams / Joule
Step 4:
Answer:
Specific heat of Aluminium is 0.89 g/J
Explanation:
during the daytime just complete your lessons of biology, during the midday timechemistry or study it in evening, at night physics and just try to complete those chapters that are difficult for you and the easier one you could do at last simple and take Sunday as a day for revision...
Give 2hrs, 1hr each chapter...
Answer:
B. Hydrogen and oxygen molecules
General Formulas and Concepts:
<u>Chemistry - Reactions</u>
- Reactants are always on the left side of the arrow
- Products are always on the right side of the arrow
Explanation:
<u>Step 1: Define</u>
Reaction RxN: 2H₂ + O₂ → 2H₂O
<u>Step 2: Identify</u>
Reactants: H₂ and O₂
Products: H₂O
The answer would be letter C - solution.
A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a beam of light to pass through a liquid in a test tube without scattering.
