1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kipiarov [429]
2 years ago
14

Give me a time table of how to revise my exam syllabus within 1 month

Chemistry
1 answer:
musickatia [10]2 years ago
4 0

Explanation:

during the daytime just complete your lessons of biology, during the midday timechemistry or study it in evening, at night physics and just try to complete those chapters that are difficult for you and the easier one you could do at last simple and take Sunday as a day for revision...

Give 2hrs, 1hr each chapter...

You might be interested in
If two clear liquids are mixed and a precipitate formed, what has probably happened?
White raven [17]
It will probably turned into a gumy
8 0
3 years ago
Read 2 more answers
How many grams of H2O are produced when 35.0 g of NaOH reacts with 17.5 g of CO,?
zhenek [66]

Answer:

2NaOH + CO2 -> Na2CO3 + H2O

1) Find the moles of each substance

\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\  =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\

2) Determine the limitting reagent

\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\

∴ Carbon dioxide is limitting as it has a smaller value.

3) multiply the limiting reagent by the mole ratio of unknown over known

n(H2O ) = 0.3976369007 × 1/2

             = 0.1988184504 moles

4) Multiply the number of moles by the molar mass of the substance.

m = 0.1988184504 × (1.008 × 2 + 16.00)

   = 0.1988184504 × 18.016

   = 3.581913202 g

Explanation:

6 0
2 years ago
After 4 half-lives 10 grams of uranium remains. How much uranium did you start with?
Free_Kalibri [48]

Answer:

i think 40 grams

Explanation:

4 0
2 years ago
determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth m
mamaluj [8]

This is an incomplete question, here is a complete question.

Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices.

(a) 1s^22s^22p^63s^23p^5

(b) 1s^22s^22p^63s^23p^63d^74s^2

(c) 1s^22s^22p^63s^23p^63d^{10}4s^24p^6

(d) 1s^22s^22p^63s^23p^63d^4s^1

Answer :

(a) 1s^22s^22p^63s^23p^5   → Halogen

(b) 1s^22s^22p^63s^23p^63d^74s^2    → Transition metal

(c) 1s^22s^22p^63s^23p^63d^{10}4s^24p^6   → Transition metal

(d) 1s^22s^22p^63s^23p^63d^4s^1   → Transition metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: ns^2np^6 where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: ns^2np^5 where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: ns^1 where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: ns^2 where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: (n-1)d^{1-10}ns^{0-2} where n is the outermost shell.

(a) 1s^22s^22p^63s^23p^5

The element having this electronic configuration belongs to the halogen family.

(b) 1s^22s^22p^63s^23p^63d^74s^2

The element having this electronic configuration belongs to the transition family.

(c) 1s^22s^22p^63s^23p^63d^{10}4s^24p^6

The element having this electronic configuration belongs to the transition family.

(d) 1s^22s^22p^63s^23p^63d^4s^1

The element having this electronic configuration belongs to the transition family.

4 0
2 years ago
What type of bond is Na3PO4?; Is Na3PO4 ionic or molecular?; Does Na3PO4 have ionic and covalent bonds?; Is Na3PO4 a polyatomic
Leni [432]

The type of the bond is present Na₃PO₄ is the ionic bond. the Na₃PO₄ is the ionic compound. yes the Na₃PO₄ is the polyatomic ion.

The Na₃PO₄ is Na⁺  and PO₄³⁻. the phosphorus is the non metal and the oxygen atom  is the non metal. the non meta and non meta form the covalent or molecular bond. the bond between the PO₄³⁻ bond is the covalent bond but the overall present in the Na₃PO₄ is the ionic bond . the bons in between the Na⁺  and PO₄³⁻ is the the ionic bond. the PO₄³⁻ id the polyatomic ion .

The bond between the positively charged ion and the negatively charged ion are called as the ionic bond and the compound form is the ionic compound.

To learn more about ionic bond here

brainly.com/question/29005103

#SPJ4

6 0
1 year ago
Other questions:
  • Seven vans each hold 6 passengers. Each passenger is carrying 20 candies divided equally among 5 small boxes. How many candies a
    5·1 answer
  • Which is FALSE regarding how elements with the same number of valence electrons will be similar?
    8·1 answer
  • A single atom of lithium can combine with a single atom of iodine to create electron energy stability for both atoms. True or fa
    5·2 answers
  • Calculate the standard enthalpy of formation of carbon disulfide (CS2) from it's elements, given that C(graphite) + O2(g) → CO2(
    9·1 answer
  • What type of silicate minerals is shown from this arrangement of silicon tetrahedron?
    11·2 answers
  • The astronaut climbed up the (blank) of the moon.
    11·2 answers
  • 300 °C would be found in which temperature range?
    13·1 answer
  • How much of a 15.0M stock solution do you need to prepare 250ml of a 2.35ml hf solution?
    7·1 answer
  • What is the iupac name of CH3-OH-CH-CH3?
    13·1 answer
  • True or false? All producers are at the top of the food web
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!