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12345 [234]
4 years ago
15

A beam of light passes though a liquid in a test tube without scattering. Which type of mixture is most likely in the test tube?

Chemistry
2 answers:
8_murik_8 [283]4 years ago
8 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Colloid is defined as the solution where particle size is between 2 to 1000 nm.  In these solutions, a physical distinction between the particle is seen. This solution can scatter light when a beam of light is passed through it.

Emulsion is defined as fine dispersion of droplets of one liquid in another liquid in which it is not soluble. There is a physical distinction between the particles and thus they can scatter the light falling on them.

True solution is defined as the solution where the size of the particle is between 0.1 nm to 1 nm. There is no physical distinction between the particles and thus they cannot scatter the light falling on them.

Suspension is defined as the solution in which the size of the particle is greater than 1000 nm. There is physical distinction between the particles and thus they can scatter the light falling on them.

Hence, the correct answer is Option C.

butalik [34]4 years ago
6 0
The answer would be letter C - solution.

A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a  beam of light to pass through a liquid in a test tube without scattering.
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A 1.00-L flask was filled with 2.00 moles of gaseous and 2.00 moles of gaseous and heated. After equilibrium was reached, it was
Bogdan [553]

Answer:

2.35

Explanation:

<em>A 1.00-L flask was filled with 2.00 moles of gaseous SO₂ and 2.00 moles of gaseous NO₂ and heated. After equilibrium was reached, it was found that 1.21 moles of gaseous NO was present. Assume that the reaction </em>

<em>SO₂ + NO₂ ⇌ SO₃ + NO </em>

<em>occurs under these conditions. Calculate the value of the equilibrium constant, K, for this reaction.</em>

<em />

Step 1: Calculate the molar concentrations

Since the reaction takes place in a 1.00 L flask, the molar concentrations are:

[SO₂]i = 2.00 M

[NO₂]i = 2.00 M

[NO]eq = 1.21 M

Step 2: Make an ICE chart

        SO₂ + NO₂ ⇌ SO₃ + NO

I       2.00   2.00       0        0

C        -x       -x         +x       +x

E    2.00-x  2.00-x    x         x

Step 3: Calculate the concentrations at equilibrium

The concentration of NO at equilibrium is 1.21 M. Then, x = 1.21.

[SO₂]eq = 2.00-1.21 = 0.79 M

[NO₂]eq = 2.00-1.21 = 0.79 M

[SO₃]eq = x = 1.21 M

[NO]eq = x = 1.21 M

Step 4: Calculate the value of the equilibrium constant, K, for this reaction

K = [SO₃] × [NO]/[SO₂] × [NO₂]

K = 1.21²/0.79² = 2.35

6 0
3 years ago
Calculate the solubility of CaF2 in g/L (Ksp = 4.0 x 10-8). 2. What is the pH of a solution containing a hydrogen ion concentrat
Pepsi [2]

Answer:

\large \boxed{1. \text{ 0.17 g/L; 2. 3.52; 3. Cl; 4. (a) +3; (b) +4; (c) +6}}

Explanation:

1. Solubility of CaF_2

(a) Molar solubility

CaF₂ ⇌ Ca²⁺ + 2F⁻

K_{\text{sp }} = \text{[Ca$^{2+}$]}\text{[F$^{-}$]}^{2}= 4.0 \times 10^{-8}\\s(2s)^{2}=4.0 \times 10^{-8}\\4s^{3} = 4.0 \times 10^{-8}\\s^{3} = 1.0 \times 10^{-8}\\s =2.2 \times 10^{-3}\text{ mol/L}

(b) Mass solubility

\text{Solubility} = 2.2 \times 10^{-3} \text{ mol/L} \times \dfrac{\text{78.07 g}}{\text{1 L }} = \text{0.17 g/L}\\\\\text{The solubility of CaF$_{2}$ is $\large \boxed{\textbf{0.17 g/L}}$}

2. pH

pH = -log [H⁺] = -log(3.0 × 10⁻⁴) = 3.52

3. Oxidizing and reducing agents

Zn + Cl₂ ⟶ ZnCl₂

\rm \stackrel{\hbox{0}}{\hbox{Zn}} + \stackrel{\hbox{0}}{\hbox{ Cl}_{2} }\longrightarrow \stackrel{\hbox{+2}}{\hbox{Zn}}\stackrel{\hbox{-1}}{\hbox{Cl}_{2}}

The oxidation number of Cl has decreased from 0 to -1.

Cl has been reduced, so Cl is the oxidizing agent.

4. Oxidation numbers

(a) Al₂O₃

\stackrel{\hbox{$\mathbf{+3}$}}{\hbox{Al}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{3}}

1O = -2; 3O = -6; 2Al  = +6; 1Al = +3

(b) XeF₄

\stackrel{\hbox{$\mathbf{+4}$}}{\hbox{Xe}}\stackrel{\hbox{-1}}{\hbox{F}_{4}}

1F = -1; 4F = -4; 1 Xe = +4

(c) K₂Cr₂O₇

\stackrel{\hbox{${+1}$}}{\hbox{K}_{2}}\stackrel{\hbox{$\mathbf{+6}$}}{\hbox{Cr}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{7}}

1K = +1; 2K = +2; 1O = -2; 7O = -14

+2 - 14 = -12

2Cr = + 12; 1 Cr = +6

8 0
4 years ago
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3 years ago
Please help me, Thank you!
Phantasy [73]

Answer:

2

Explanation:

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Electrons are the negatively charged particles within an atom. Therefore the total number of electrons surrounding the nucleus in the given specie is 7.

 So;

   We have 2 core electrons

   And 5 valence electrons

The core electrons are the inner orbital electrons.

The valence electrons are the outermost electrons.

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3 years ago
Scientific knowledge results from the interaction of scientists who are investigating natural phenomena. Which of these BEST des
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Answer:

5ywhxhghghghfhffgffgffg

Explanation:

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3 years ago
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