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3 years ago

A beam of light passes though a liquid in a test tube without scattering. Which type of mixture is most likely in the test tube?

Chemistry

2 answers:

8_murik_8 [283]3 years ago

8 0

Answer: The correct answer is Option C.

Explanation:

Colloid is defined as the solution where particle size is between 2 to 1000 nm. In these solutions, a physical distinction between the particle is seen. This solution can scatter light when a beam of light is passed through it.

Emulsion is defined as fine dispersion of droplets of one liquid in another liquid in which it is not soluble. There is a physical distinction between the particles and thus they can scatter the light falling on them.

True solution is defined as the solution where the size of the particle is between 0.1 nm to 1 nm. There is no physical distinction between the particles and thus they cannot scatter the light falling on them.

Suspension is defined as the solution in which the size of the particle is greater than 1000 nm. There is physical distinction between the particles and thus they can scatter the light falling on them.

Hence, the correct answer is Option C.

butalik [34]3 years ago

6 0

The answer would be letter C - solution.

A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a beam of light to pass through a liquid in a test tube without scattering.

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3 years ago

This graph shows two curves pertaining to a hydrogen s orbital.

fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function which is denoted by $R_{nl}(r)$ shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as $R^{2}_{nl}(r)$ shown in blue color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by 'n'.

It is observed that for any atomic orbital, the total number of nodes will be n-1 .

Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.

Hence, there will be only radial nodes, which is

(n−1 = total number of radial nodes in s orbitals)

According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.

Answer 2) The radial nodes are observed in I'm seeing radial nodes at

$1.9a_{0}$ , $6.4a_{0}$ , $13.9a_{0}$ and $27.0a_{0}$ .

where $a_{0}$ represents the hydorgen bohr atomic radius = 0.0529177 nm

Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

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3 years ago

Read 2 more answers

The change of state from a gas to a liquid. Single choice.

elena-14-01-66 [18.8K]

Precipitation :)
Hope it helps

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3 years ago

Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 , and aqueous nickel(II) chl

pantera1 [17]

Answer:

NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)

Explanation:

Soluble ionic compounds exist as ions in solution.

Na 2CO3, will contain Na2CO3 (aq) --> 2Na ^+ (aq) + CO2 ^-3 (aq)

The same way, a solution of calcium chloride,

CaCl 2, will contain CaCl2 (aq) --> Ca2^+ (aq) + 2Cl^− (aq)

Mixing both solution, the calcium cations

Ca 2^+ , will apir up with the carbonate anions, CO2^−3 , and form the Insoluble calcium carbonate, CaCO ^3, which precipitates out of solution.

The complete ionic equation, which features all the ions that are present in solution, will be like this

2 Na^+ (aq) + CO2^−3 (aq) + Ca2^+ (aq) + 2Cl^− (aq) --> CaCO 3 ↓ (s) + 2Na^+ (aq) + 2Cl^− (aq)

Notice that you have two sodium cations and two chloride anions on the products' side, which is why you have 2NaCl

NiCl2 (aq) + Na2CO3 (aq) ---> NiCO3 (s) + 2NaCl (aq)

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3 years ago

Trick to change word equation to chemical equation

Elden [556K]

Answer:

actually word equation has the names and we need to write molecular formula in chemical eqn. so I don't think there is sort of trick.You just need to memorise the molecular formula of chemicals.

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3 years ago