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12345 [234]
3 years ago
15

A beam of light passes though a liquid in a test tube without scattering. Which type of mixture is most likely in the test tube?

Chemistry
2 answers:
8_murik_8 [283]3 years ago
8 0

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Colloid is defined as the solution where particle size is between 2 to 1000 nm.  In these solutions, a physical distinction between the particle is seen. This solution can scatter light when a beam of light is passed through it.

Emulsion is defined as fine dispersion of droplets of one liquid in another liquid in which it is not soluble. There is a physical distinction between the particles and thus they can scatter the light falling on them.

True solution is defined as the solution where the size of the particle is between 0.1 nm to 1 nm. There is no physical distinction between the particles and thus they cannot scatter the light falling on them.

Suspension is defined as the solution in which the size of the particle is greater than 1000 nm. There is physical distinction between the particles and thus they can scatter the light falling on them.

Hence, the correct answer is Option C.

butalik [34]3 years ago
6 0
The answer would be letter C - solution.

A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a  beam of light to pass through a liquid in a test tube without scattering.
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We are told 2x = partial pressure of SO₃ is 0.47 atm at equilibrium, so we can determine the partial pressures of  SO₂ and O₂ as follows:

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Now we can calculate Kp:

Kp = 0.47² /[ ( 2.83 )² x 0.56 ] = 0.049 ( rounded to 2 significant figures )

Note that we have extra data in this problem we did not need since once we setup the ICE table for the equilibrium we realize we have all the information needed to solve the question.

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