79% of Mg-24
10% of Mg-25
11% of Mg-26
18.96 + 2.5 + 2.86 = 24.32u
4% mass / volume :
4 g ---------> 100 mL
1.2 g ------- ? mL
V = 1.2 * 100 / 4
V = 120 / 4
V = 30 mL
hope this helps!
Actually the correct answer must be:
The limiting reactant in the reaction is the one which has
the lowest ratio of moles available
over coefficient in the balanced equation
This is because the actual mass or number of moles of the
reactant does not directly dictate if it is a limiting reactant, this must be
relative to the other reactants.
So the answer is:
e. none of the above
Answer :
The basic rules for naming of hydrocarbons are :
First select the longest possible carbon chain.
The longest possible carbon chain should include the carbons of double or triple bonds.
The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne.
The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.
The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.
If two or more similar alkyl groups are present in a compound, the prefixes di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.
Answer:
The oxidation state of the carbon is +4.
Explanation:
Calcium is in group 2 of the periodic table, therefore, its oxidation state is +2.
The oxidation state of the oxygen is -2.
As the compound is neutral, the sum of the oxidation states of all atoms must be 0.
Oxidation State Ca + Oxidation State C + (Oxidation State O)×3 = 0
+2 + x + (-2)×3 = 0
2 + x - 6 = 0
x = 6 -2
x = 4
Hence, the oxidation state of the carbon is +4.
