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Phoenix [80]
2 years ago
7

Find the area of the polygon. 2 cm 3 cm 1 cm 3 cm 4 cm

Mathematics
1 answer:
Natasha2012 [34]2 years ago
4 0

Answer:

the area of the problem is 20

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In a bag of trail mix, there are 5 cups of nuts for every 2 cups of chocolate candies. If there are 12 cups of nuts in a bag of
Katyanochek1 [597]

Answer:

5

Step-by-step explanation:

7 0
2 years ago
Vince has a movie rental gift card that start with $50 on it. Each movie he rents costs him $4.
Leto [7]

Linear function: d = -4m+50 (that's a negative 4 btw)

Slope: -4

y-intercept: 50

I'm truly sorry but I forgot how to do the last one :(


5 0
2 years ago
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The volume of the spheres is 500/3 pie cubic units What is the value of X?
Julli [10]

Answer:

125

Step-by-step explanation:

500 ÷ 4 = 125

I think this is the right answer. sorry if I'm wrong.

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3 years ago
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How do you write 4(8m-7n)+6(3n-4m) in expanded form
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4(8m-7n)+6(3n-4m) =32m-28n+18n-24m=8m-10n


6 0
3 years ago
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Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
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