<span>2x + y = 6
2x + y - 6 = 0
answer is </span>2x + y - 6 = 0
hope that helps
Answer:
<em>4x^3(x^2 - 5)</em>
Step-by-step explanation:
First, try to factor a common factor.
GCF of 4 and -20 is 4.
GCF of x^5 and x^3 is x^3.
Factor out 4x^3.
4x^5 - 20x^3 =
= 4x^3(x^2 - 5)
<h3><em>(8)2+(x)2=(10)2</em></h3><h3><em>64+x2=100</em></h3><h3><em>x2=100-64</em></h3><h3><em>x2=36</em></h3><h3><em>x=6</em></h3><h3><em>BE = 6</em></h3><h3><em>hope it helps..stay blessed...thank you....</em></h3>
Answer:
(D) -k2 + k - 13
Step-by-step explanation:
Pulling out like terms :
2.1 Pull out like factors :
-k2 + k - 13 = -1 • (k2 - k + 13)
Trying to factor by splitting the middle term
2.2 Factoring k2 - k + 13
The first term is, k2 its coefficient is 1 .
The middle term is, -k its coefficient is -1 .
The last term, "the constant", is +13
Step-1 : Multiply the coefficient of the first term by the constant 1 • 13 = 13
Step-2 : Find two factors of 13 whose sum equals the coefficient of the middle term, which is -1 .
-13 + -1 = -14
-1 + -13 = -14
1 + 13 = 14
13 + 1 = 14
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-k2 + k - 13
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