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Katena32 [7]
3 years ago
9

The square numbers can be defined by the recursive formula a1 = 1, and an = an-1 + (2n - 1), where n > 1. The first five squa

re numbers are
Mathematics
2 answers:
liberstina [14]3 years ago
4 0
<span>1, 4, 9, 16, and 25. Use the formula to get a2 = 1 + (2*2 - 1) = 4, a3 = 4 + (2*3 - 1) = 9, etc. Also notice that for all n, an = n2.</span>
masya89 [10]3 years ago
4 0

Answer:Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula:

a1 = 8  

an = 2.9an – 1 – 0.2(an – 1)2

Which of the following describes what is happening to the insect population for the first five years?

Step-by-step explanation:

Its D on edu

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Which theorem can be used to prove that the triangles in<br> the figure below are congruent?
Minchanka [31]

Answer:

There are 5 theorem to prove the triangles are congruent. They are:

  • SSS
  • SAS
  • ASA
  • RHS

6 0
2 years ago
The sum of two numbers is 18. One number is 2 more that for times the other. Find the numbers.
ipn [44]
X+2x=18
3x=18
x=6

2(6)=12

hope this helps
4 0
3 years ago
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A population of butterflies is growing 5% each month. Write an equation that expresses the number of butterflies at time x if th
tiny-mole [99]
500 • .05(x) is the answer
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3 years ago
State the quotient and remainder when the first polynomial is divided by the second. 3x^4-3x^3-11x^2+6x-1; x^3+x^2-2
djverab [1.8K]

3x^4=3x\cdot x^3, and 3x(x^3+x^2-2)=3x^4+3x^3-6x. Subtracting this from the numerator leaves a remainder of

(3x^4-3x^3-11x^2+6x-1)-(3x^4+3x^3-6x)=-6x^3-11x^2+12x-1

-6x^3=-6\cdot x^3, and -6(x^3+x^2-2)=-6x^3-6x^2+12. Subtracting this from the previous remainder gives a new remainder of

(-6x^3-11x^2+12x-1)-(-6x^3-6x^2+12)=-5x^2+12x-13

-5x^2 has no factors of x^3, so we stop here. Then

\dfrac{3x^4-3x^3-11x^2+6x-1}{x^3+x^2-2}=3x-\dfrac{6x^3+5x^2-6x+1}{x^3+x^2-2}

=3x-6-\dfrac{5x^2-12x+13}{x^3+x^2-2}

5 0
3 years ago
Read 2 more answers
Solve the inequality T&gt; L+D
nirvana33 [79]

Answer:

solving for t= t>d+l

For l= l<t-d

Then for d=d<t-l

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2 years ago
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