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3 years ago

14

Solve y=-x2-2x-2 y=x-4

1 answer:

Free_Kalibri [48]3 years ago

5 0

Step-by-step explanation:

y−x2+2x=−4y-x2+2x=-4 , y+x=2

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If the frequency of hba homozygotes is 0.1 what is the value of p2

Angelina_Jolie [31]

we know that

p^2 is the the frequency of hba homozygote

we are given

frequency of hba homozygotes is 0.1

so,

p^2 =frequency of hba homozygotes

we can plug values

and we get

$p^2=0.1$ ..............Answer

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3 years ago

Rewrite the equation in standard form y - 3 = 4(x - 3)

kumpel [21]

Answer:

y=4x-9

Step-by-step explanation:

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3 years ago

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A rectangle has a width of 9 cm, and a diagonal of 15 cm. Find the length.

iren2701 [21]

The answer is
$9 { + 15 {}^{2} }^{= \sqrt{108}$

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3 years ago

Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0

3 years ago

Is it a,b,c or d I have 5 minutes please hurry

snow_lady [41]

Answer:

its a

Step-by-step explanation:

4/12 = 1/3

5 0

3 years ago

Read 2 more answers