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Igoryamba
3 years ago
12

elect the proper interpretation of a confidence interval for a mean at a confidence level of C % . a range of values produced by

a method such that C % of confidence intervals produced the same way contain the sample mean a range of values such that the probability is C % that a randomly selected data value is in that range a range of values that contains C % of the sample data in a very large number of samples of the same size a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time a range of values such that the probability is C % that the population mean is in that range
Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0

Answer:

a range of values such that the probability is C % that a rndomly selected data value is in that range

Step-by-step explanation:

complete question is:

Select the proper interpretation of a confidence interval for a mean at a confidence level of C % .

a range of values produced by a method such that C % of confidence intervals produced the same way contain the sample mean

a range of values such that the probability is C % that a randomly selected data value is in that range

a range of values that contains C % of the sample data in a very large number of samples of the same size

a range of values constructed using a procedure that will develop a range that contains the population mean C % of the time

a range of values such that the probability is C % that the population mean is in that range

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Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
Which number is a rational number<br> A. 7<br> B. 7.07....<br> C. 8.12....<br> D. 9.94...
Lady bird [3.3K]
Answer:

A

Explanation:

All of the other choices are ongoing decimals which make the irrational numbers
7 0
3 years ago
For the function, f(x)=(9x+7)/(2x+4)
AVprozaik [17]
A. f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. \frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714 - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.
5 0
3 years ago
What is -9-x when x= 4.3
Setler79 [48]

Answer: -13.3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the equation. Simplify your answer. <br><br><br>3(x - 2) = 6(5 + x)<br><br> x = [?]​
sammy [17]

Answer:

-12 =x

Step-by-step explanation:

3(x - 2) = 6(5 + x)

Distribute

3x -6 = 30 +6x

Subtract 3x from each side

3x-6-3x = 30 +6x-3x

-6 = 30+3x

Subtract 30 from each side

-6 -30 = 30+3x-30

-36 = 3x

Divide each side by 3

-36/3 = 3x/3

-12 =x

8 0
3 years ago
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