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Pie
3 years ago
11

There are 20 mice in a 5 m2 field ecosystem. The population density of mice is _____.

Chemistry
1 answer:
Anna11 [10]3 years ago
3 0

Answer:

4per m 2

20 mice divided by 5 so it will be 4 per m 2

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In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)
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It is called, Noble gas
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Jane is sliding down a slide. What kind of motion is she demonstrating?
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A) Translational motion or the first option would be your answer.
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4 years ago
If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79
Helen [10]
1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass. 

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol

200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4

3) convert moles of CuSO₄ to moles of Cu

1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu

4) convert moles of Cu to grams using it's molar mass.

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I did it step-by-step as the explanation but you can do all of this in one step. 

200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu


4 0
4 years ago
0 / 5 pts Question 3 In the reaction of aluminum with iron III oxide, if you start with 54.2 grams of aluminum, how many grams o
adelina 88 [10]
Could you please mark me as brainliest?

Answer: 160.40 g Fe2O3 are needed.

Explanation:

Balanced equation: 2 Al + Fe2O3 —> Al2O3 + 2Fe

54.2 g Al * 1 mol Al / 26.98 g Al * 1 mol Fe2O3 / 2 mol Al * 159.69 g Fe2O3 / 1 mol = 160.40 g Fe2O3 are needed.
3 0
3 years ago
If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?
Ksenya-84 [330]

Answer:

=> 0.10 moles

Explanation:

The question is asking us to find the moles of NaCl cid formed.

We have been provided with;

0.10 L of 1.0 M NaOH.

We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.

This means that;

1.0 M is contained in 1.0 L.

X mol is contained in 0.10 L

x \: mol \:  =  \frac{0.1 \times 1.0}{1.0}  \\  = 0.10 \: mol

= 0.10 moles of NaCl formed

8 0
2 years ago
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