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4 years ago

1. Estuaries may be either brackish or freshwater systems. True O False

Chemistry

1 answer:

zzz [600]4 years ago

4 0

Answer:

False - Estuaries are formed due to both brackish and freshwater.

Explanation:

Hope this Helps!!!

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Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2

Karolina [17]

Answer:

The mole fractions:

$x_{HBr}=\frac{100mol}{318.5}=0.314$

$x_{Br_2}=\frac{78mol}{318.5}=0.245$

$x_{H_2O}=\frac{78mol}{318.5}=0.245$

$x_{O_2}=\frac{62.5mol}{318.5}=0.196$

Explanation:

The reaction described is:

$2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)$

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

$n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78$

(the 0.78 is because of the fractional conversion)

$n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25$

(the 1.25 is because of the oxygen excess)

$n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}$

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

$nn_{HBr}=100 mol HBr$

$n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *100mol HBr*0.78$

$n_{Br_2}=78 mol Br2$

$n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *100 mol HBr*1.25$

$n_{O_2}=62.5 mol O_2$

$n_{H_2O}=n_{Br_2}= 78 mol$

$n_{total}=(78+78+100+62.5)mol= 318.5mol$

The mole fractions:

$x_{HBr}=\frac{100mol}{318.5}=0.314$

$x_{Br_2}=\frac{78mol}{318.5}=0.245$

$x_{H_2O}=\frac{78mol}{318.5}=0.245$

$x_{O_2}=\frac{62.5mol}{318.5}=0.196$

4 0

3 years ago

What type of evidence does the author use to support his argument that students should be required to complete service hours in

SpyIntel [72]

Answer:C

Explanation:
C. The author presents rational and logical reasons to support his argument

4 0

3 years ago

Find the molarity of the following solution:

CaHeK987 [17]

Answer:

2.67 M

Explanation:

Molarity, which is the molar concentration of a substance, can be calculated using the formula;

M = n/V

Where;

M = molarity (M)

n = number of moles (mol)

V = volume (Litres)

Based on the provided information in this question, mass of lithium sulfate (Li2SO4) = 734g, volume = 2.5L

Using mole = mass/molar mass

Molar mass of Li2SO4 = 7(2) + 32 + 16(4)

= 14 + 32 + 64

= 110g/mol

Mole = 734/110

Mole (n) = 6.67moles

Molarity = n/V

Molarity = 6.67/2.5

Molarity = 2.668

Molarity of Li2SO4 in the solution is 2.67 M

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3 years ago

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Why must a chemical equation be balanced before you can determine mole ratios

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Calculate the number of moles for each element. n=m/M Then compare, and which ever one is lowest is the limiting reactant because no more products can form without one or the other.

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3 years ago

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Consider the Van der Vaals equation of state: (????+????????????)(????−????)=???????????? where p is pressure, V is volume, n is

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Answer:

Units of a = $\frac{atm\ L^2}{mol^2}$