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Crank
3 years ago
5

Nuclide A has a half-life of 4 days, and nuclide B has a half-life of 16 days. At the beginning of an experiment, a sample conta

ins 2 nuclei of nuclide A and 218 nuclei equal of nuclide B. How long will it take before the numbers of nuclei of the two nuclides are equal?
Chemistry
2 answers:
GREYUIT [131]3 years ago
8 0

Answer: ladadadadadadasasasasassassaasss

Explanation:

i poop my pants

Zolol [24]3 years ago
3 0

Answer:

can't say...... . . please make me as brainlist

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An atom is electrically neutral when...
Charra [1.4K]

Answer:

The number of protons and electrons are equal.

Explanation:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.

3 0
3 years ago
If you have 9900 g of donuts, how many donuts do you have if each donut has a mass of 159 g?
tensa zangetsu [6.8K]
Just divide 9900/159 then ur get the total(hope it helps)
8 0
3 years ago
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What are valence electrons of an atom used for?
Murrr4er [49]

In chemistry and physics, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.
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3 years ago
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ZanzabumX [31]
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Explanation- equals 459
3 0
3 years ago
An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.
aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0
3 years ago
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