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e-lub [12.9K]
2 years ago
12

How many moles are present in 2.95 x1024 molecules of water (H20)

Chemistry
1 answer:
DerKrebs [107]2 years ago
4 0

ANSWER: 3020.8 moleclues of water (h20)           Explanation I did the math and the quiz

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In a sample of oxygen gas at room temperature, the average kinetic energy of all the balls stays constant. Which postulate of ki
Levart [38]

Answer:

Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.

Explanation:

When a gas is paced in a container, the molecules of the gas have little or no intermolecular interaction between them. There is a lot of space between the molecules of the gas.

The gas molecules move at very high speed and collide with each other and with the walls of container.

The collision of these particles with each other is perfectly elastic hence the kinetic energy of the colliding gas particles do not change.

7 0
3 years ago
A chemical is said to be stable if it is difficult to get it to react. This property of a chemical is a __________ property.
ivann1987 [24]

Answer:

physical

Explanation:

<h2><u>Fill in the blanks </u></h2>

A chemical is said to be stable if it is difficult to get it to react. This property of a chemical is a <u>physical</u>  property

4 0
2 years ago
What is the percent of oxygen by mass in C2H402
Rom4ik [11]

Answer:

53.3 %.

Explanation: C2H4O2. = 2 * 12.011 + 4 * 1.008 + 2 * 15.999. = 60.052.

6 0
2 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
3 years ago
1.) When blood flow is gone from the extremities for too long, the cells start to die. Depending on the severity of the
valkas [14]

Answer:

its A

Explanation:

because frostbite kills the nerves

5 0
2 years ago
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