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e-lub [12.9K]
2 years ago
12

How many moles are present in 2.95 x1024 molecules of water (H20)

Chemistry
1 answer:
DerKrebs [107]2 years ago
4 0

ANSWER: 3020.8 moleclues of water (h20)           Explanation I did the math and the quiz

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Consider four different samples: aqueous LiBr, molten LiBr, aqueous LiF, and molten LiF. Current run through each sample produce
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Answer:

Following are the solution to the given question:

Explanation:

Please find the matching in attached file.

During the electrolysis of Molten LiBr : Li is reduced and Br are oxidized .

Lithium Metal is produced at the Cathod during the electrolysis of Molten LiBR .

In the aquous LiBr : In aquous LiBr potential of Li is greater than the of water then Li is reduced to produce solid Li ion.  As well As aqueous LiF ( electrolysis)and Molten LiF electrolysis produce the gas.  

aqueous LiF: Oxygen gas.

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5 0
2 years ago
how does atomic radius change as you move down a group/family and as you move across a period/row on the periodic table? what ca
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When going down a group the no of orbits increases. That is n value increases (n=principle quantum number). When the number of atomic orbitals increases, the radius gradually increases. (going down the group means the number of obits that electrons can fill will increase)

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3 years ago
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san4es73 [151]

Answer:

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6 0
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If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m
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Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

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We can take π as 3.14 and we get;

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Soving we get;

A =  7850 μm^{2}  

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here 1 μm^{2} = 7850 μm^{2} dye molecules.

Therefore, 10 fluorescent molecules will need;  

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.

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3 years ago
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