Answer:
Number of cheaper dresses sold is 35
Number of expensive dresses sold is 15
Step-by-step explanation:
Given:
Cost of cheaper dresses = $90
Cost of expensive dresses = $140
Total cost of the dresses = $5250
To Find:
Number of cheaper dress = ?
Number of expensive dress = ?
Solution:
Let
The number of cheaper dresses be x
The number of expensive dresses be y
(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250
= $5250
It is given that the 20 more of the cheaper dresses than the expensive dresses is sold
So,
number of cheaper dress = 20 + number of expensive dress
x = 20 + y---------------------------------------(1)







y = 15
Substituting y in (1)
x = 20 +15
x= 35
♥ Solve:
31/100
50/100
50 is larger than 31
Therefore 5/10 is larger than 31/100
so, uh, i think the answe is actually 5. Since 5^2 is 25, minus 5 is 20, and 5 minus 1 is 4, 20 divided by 4 is 5. i hope that helps.
Set it up as an equation: 12 + 6x = 47
(x is the reduced fee)
12 + 6x = 47
12 - 12 + 6x = 47 - 12
6x = 35
x = 35/6
x = 5.83 repeating (only the 3 is repeating)