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____ [38]
3 years ago
9

How do you find the slope of a point line function !

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

To find the slope of a function written in point-slope form, we must first know what point slope form is. Point slope form is:


y - y₁ = m[x - x₁]


In this function, m is the slope, so the find the slope of a point-slope line function, we just have to look at the value right outside the parenthesis on the right side of the equation.

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John weighs three times as much as Karen. Two times John's weight plus Karen's weight is 875 pounds. How much does John weigh? H
Leokris [45]

Answer:

John- 375

Karen- 125

Step-by-step explanation:

Answer 1...

j =3k

2j + k = 875

substituting the first eqn into the 2nd

2(3k) + k = 875

6k+ k =875

7k = 875

k =875/7 =125

thus j = 3(125) =375

3 0
2 years ago
Read 2 more answers
PLEASEEE EXPLAIN AND HELP
Firdavs [7]

The length of the unknown sides of the triangles are as follows:

CD = 10√2

AC = 10√2

BC =  10

AB = 10

<h3>Triangle ACD</h3>

ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.

  • c² = a² + b²

where

c = hypotenuse side = AD = 20

a and b are the other 2 legs

lets use trigonometric ratio to find CD,

cos 45 = adjacent / hypotenuse

cos 45 = CD / 20

CD = 1 / √2 × 20

CD = 20 / √2 = 20√2 / 2 = 10√2

20² - (10√2)² = AC²

400 - 100(2)  = AC²

AC² = 200

AC = √200 = 10√2

<h3>Triangle ABC</h3>

ΔABC is a right angle triangle too. Therefore,

  • AB² + BC² = AC²

Using trigonometric ratio,

cos 45 = BC / 10√2

BC = 10√2 × cos 45

BC = 10√2 × 1 / √2

BC = 10√2 / √2 =  10

(10√2)² - 10² = AB²

200 - 100 = AB²

AB² = 100

AB = 10

learn more on triangles here: brainly.com/question/24304623?referrer=searchResults

5 0
2 years ago
Guess my favorite movie for brainliest no hints 50 points and brainliest to who gets it but only the first two people to guess a
Marianna [84]

Answer:

planet of the apes?

3 0
3 years ago
Multiply 3x(2x-1) by following these steps
siniylev [52]

Answer:

6x^2-3x

Step-by-step explanation:

3x(2x-1)= \\\\3x(2x)-3x(1)= \\\\6x^2-3x

Hope this helps!

8 0
3 years ago
Read 2 more answers
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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