The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

1 answer:

7 0

The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.

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How do you tell if it's possible to make a triangle out of these side lengths? PLZ HELP!!!!!

Nastasia [14]

Answer:

Step-by-step explanation:

square root of 73 is about 8.5

square root of 10 is about 3. multiply by 3, you get 9.

square root of 7 is about 2.6. multiply by 5, you get 13.

when determining if you can make a triangle, if all variants of two sides can add up to be greater than the third side, you can make the triangle. so 8.5+9 > 13; 13+9 > 8.5; 13+8.5 > 9. this means it can make a triangle and all you have to do is order the sides.

8.5 is smallest which corresponds to angle c because it's opposite. 9 goes to angle a, then finally 13 goes to angle b. thus, angles c, a, b is the order.

side note: the smallest side length will always correspond with the smallest angle.

hope this helps :)

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pickupchik [31]

P(a U b) = p(a) + p(b) - p(a ∩ b)

<=>

p(a ∩ b) = p(a) + p(b) - p(a U b)

I let you do the maths :)

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