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ivolga24 [154]
3 years ago
13

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

Mathematics
1 answer:
lakkis [162]3 years ago
7 0

The smallest perimeter is 72.44 inches. The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. As much as possible, the sum of the length of the two remaining side must be greater than the other side. Given the side is 30, then the sum of the two remaining sides should be greater than 30 inches.

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Show work <br> Need fast!!! <br><br> 4(1/3+ 1/3+ 1/3)
aalyn [17]

Answer:

4

Step-by-step explanation:

calculate the sum 4*1 any expression is multiplied by 1 remains the same solution is 4

7 0
3 years ago
What is the Median for the following set of numbers? ​21 23 76 47 55 135 45 30 17
Leno4ka [110]

Answer:

Median = 45

Step-by-step explanation:

We are given the following data set:

21, 23, 76, 47, 55, 135, 45, 30, 17

Median is the number that divides the data into two equal parts.

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

17, 21, 23, 30, 45, 47, 55, 76, 135

Sample size = 9, which is odd

Median =

\dfrac{9+1}{2}^{th}\text{ term} = \dfrac{10}{2}^{th}\text{ term} = 5^{th}\text{ term}\\\\= 45

The median of given set of numbers is 45.

7 0
3 years ago
What is the probability that a randomly selected contestant won a prize, given that the contestant was female write the probabil
pantera1 [17]

We have given the table of number of male and female contestants who did and did not win prize

The probability that a randomly selected contestant won prize given that contestant was female is

P(contestant won prize / Contestant was female)

Here we will use conditional probability formula

P(A/B) = \frac{P( A and B)}{P(B)}

Let Event A = selected contestant won prize and

event B = selected contestant is famale

Then numerator entity will

P(A and B) = P(Contestant won prize and Contestant is female)

= Number of female contestant who won prize / Total number of contestant

= 3 /(4+9+3+10)

= 3 / 26

P(A and B) = 0.1153

P(B) = P(contestant is female )

= Number of female contestant / Total number of contestants

= (3+10) / 26

P(B) = 0.5

Now P(A / B) = \frac{P( A and B)}{P(B)}

= 0.1153 / 0.5

P(A / B) = 0.2306

The probability that randomly selected contestant won prize given that contestant is female is 0.2306

Converting probability into percentage 23.06%

The percentage that randomly selected contestant won prize given that contestant is female is 23%

3 0
3 years ago
What is the coordinates of {2, 1} and {2, 4}?
blondinia [14]
Xm=(2+2)/2=2 Ym=(1+4)/2=2.5 (2,2.5)
7 0
3 years ago
Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
1 year ago
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