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TiliK225 [7]
3 years ago
13

Please help if you can!

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Given:

The figure of a triangle DEF.

To find:

The coordinate of image of given triangle after reflection over y-axis.

Solution:

The vertices of given triangle are D(1,4), E(4,3), F(2,0).

If a figure is reflected over the y-axis, then the rule of reflection is

(x,y)\to (-x,y)

Using this rule, we get

D(1,4)\to D'(-1,4)

E(4,3)\to E'(-4,3)

F(2,0)\to F'(-2,0)

Therefore, the coordinates of image are D'(-1,4), E'(-4,3) and F'(-2,0).

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How would I solve <br> -6.11 + b = 14.321
Studentka2010 [4]

Answer:

b=20.431

Step-by-step explanation:

you just add  6.11 to both sides. on the left side the -6.11 and +6.11 cancel out and on the right side you will just add 6.11 to 14.321. when you add 14.321 and 6.11 you get 20.431. therefore, b=20.431

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLYIST HELP FASTTT
marysya [2.9K]

Answer:

im reallly sorry

Step-by-step explanation:

5 0
2 years ago
Need help
aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters are given as follows:

\mu = 959, \sigma = 263, n = 37, s = \frac{263}{\sqrt{37}} = 43.24

Item a:

The probability is <u>one subtracted by the p-value of Z when X = 984</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{984 - 959}{263}

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

Item b:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{984 - 959}{43.24}

Z = 0.58

Z = 0.58 has a p-value of 0.7190.

1 - 0.719 = 0.281.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
1 year ago
Solve for g.<br>-6g – 5 + 5 = 2 – 8g
sergey [27]

Answer:

8.875

Step-by-step explanation:

The +5 and -5 cancel, so you are left with -69=2-8g. Subtract two on both sides to get -71=-8g then divide both side by -8 to get g=8.875.

6 0
2 years ago
Read 2 more answers
A box contains four 10 nf and eight 100 nf capacitors. (a) what is the probability of obtaining at least two 10 nf capacitors if
grigory [225]

there are 4 of the 10-nf and 8 of the 100-nf capacitors which is a total of 12 items.

the probability of drawing a 10-nf is: 4 out of 12 = \frac{1}{3}

the probability of drawing a 100-nf is: 8 out of 12 =  \frac{2}{3}

(a)  "at least two" means: 2 or 3 or 4

Probability of 2 (10's) and 2 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{2}{3} x \frac{2}{3} = \frac{4}{81}

Probability of 3 (10's) and 1 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{2}{3} = \frac{2}{81}

Probability of 4 (10's) and 0 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{1}{3} = \frac{1}{81}

2 or 3 or 4: \frac{4}{81} + \frac{2}{81} + \frac{1}{81} = \frac{7}{81}

(b) without replacement

Probability of 2 (10's) and 2 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{8}{10} x \frac{7}{9} = \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9}

Probability of 3 (10's) and 1 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{8}{9} = \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9}

Probability of 4 (10's) and 0 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{1}{9} = \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9}

2 or 3 or 4: \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9} = \frac{672 + 192 + 24}{12 x 11 x 10 x 9} =  \frac{888}{12 x 11 x 10 x 9}  =  \frac{111}{1485}


8 0
3 years ago
Read 2 more answers
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