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cupoosta [38]
2 years ago
13

Write the relation as a set of ordered pairs​

Mathematics
2 answers:
Rashid [163]2 years ago
8 0

Answer:

A.

Step-by-step explanation:

sukhopar [10]2 years ago
6 0

Answer:

a

Step-by-step explanation:

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LeShana loaned Deena $480. Deena paid the money back with simple interest of 5% at the end of 2 years. How much money did Deena
Amanda [17]
480$ --100%
x$  -------5%
x=480*5/100=24$
8 0
3 years ago
Arnold and jamie are both performing the same experiment. Arnold does 20 trials and gets 7 positive results. Jamie does 10 trial
Gnoma [55]

Answer:

B

Step-by-step explanation:

This is all 1/3 of the number of times the experiment was tried to put in perspective john has 10 apples and he gives 3 away that's about 1/3 of the amount of apples

3 0
2 years ago
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Ralph is leasing a car worth $24,000 for three years. His leasing company says that the car Ralph is leasing will only be worth
atroni [7]
The answer is C.) 33% i believe. Excuse me if i'm wrong!!!!!
3 0
3 years ago
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A professional organization sells term life insurance and major medical insurance. Of those who have just life insurance, 60% wi
kherson [118]

Answer:

The answer is "0.765 and 0.2353".

Step-by-step explanation:

Please find the complete question in the attached file.

In point a:

P(a substantive term only)=0.75-0.2 =0.55

P(major health insurance only) = 0.45-0.20=0.25

P(both)= 0.20

P(renewal) =P(insurance and renewal term only)+P (substantial and renewable health insurance only)+P (both and renew)

=0.55\times 0.7+0.25 \times 0.8+0.2 \times 0.9 \\\\ =0.765

In point b:

In reality, the probability of having both life and major medical insurance provided the policyholder would renew next year

= \frac{\text{P(both and renew)}}{\text{P(renew)}}

=\frac{0.2\times 0.9}{0.765}\\\\=0.2353

4 0
3 years ago
There were 75 roasted turkeys at Ally's Eats. Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats. If Ally's Eats had 5/6
Sever21 [200]

Answer:

75 roasted turkeys.

Step-by-step explanation:

Ally's Eats had 75 roasted turkeys.

Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats, hence, the number of roasted turkeys Bob's Goods had is:

4/5 * 75 = 60 roasted turkeys

Ally's Eats had 5/6 as many roasted turkeys as Charlotte's Market. In other words, Charlotte's market had 6/5 as many roasted turkeys as Ally's Eats:

6/5 * 75 = 90 roasted turkeys.

The average is given as the sum of all toasted turkeys in the three shops divided by 3. Hence:

A = (75 + 60 + 90) / 3

A = 225 / 3 = 75 roasted turkeys

The average number of roasted turkeys in the three shops is 75.

7 0
3 years ago
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