Here we need to know SOH CAH TOA. So first thing first we know tan is negative in quadrant 2 because the x value is negative in quadrant to and since tan is opposite/adjacent (y/x) it will be negative. so now think of a standard graph with 4 quadrants. Now imagine or draw a diagonal line in quadrant 2. Now draw a dotted line straight down from the end of that point to the x axis creating a right triangle. theta is the angle closest to the origin of the graph. SO we know sinΘ= 1/4 and sin= opposite/hypotenuse. So the opposite line (the vertical one we drew down to touch the x axis) is 1 and the hypotenuse is 4. Well to find tan we need the adjacent line (horizontal) which we will find using the Pythagorean theorem a² + b² = c² 1² + b² = 4² 1 + b² = 16 b² = 15 b =√15 so the adjacent side of our triangle is -√15 because remember we are in the 2nd quadrant which is a negative x. SO since tan= opposite/adjacent: tan= 1/ -√15 or -1/√15 this could be your answer unless your teacher doesn't want radicals on the bottom of a fraction. to remove simply multiply the top and bottom by the radical. -1/√15 (-1 × √15) / (√15 × √15) -√15/15 is ur final answer
It is B and E because it’s exponent matches the equation. In B, there are 2 fives and the exponential form shows 5 to the power of 2. In E, there are 6 sevens and the exponential form shows 7 to the power of 6.
