All categories

3 years ago

Can anyone help me, i need like 6 more of these i’ll mar brainliest

Mathematics

2 answers:

Yuki888 [10]3 years ago

3 0

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 2 Squareroot(2)

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

eimsori [14]3 years ago

3 0

I just answered so you could give this person brainliest

You might be interested in

A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of

ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

7 0

3 years ago

Explain why P(A|D) and P(D|A) from the table below are not equal.

trasher [3.6K]

Answer:

The Probability that Event A and Event D occur is equal to the probability Event A occurs times the probability that Event D occurs, given that A has occurred.

$P(A\cap D)=P(A)\cdot P(D/A)$

We can find the values of $P(A/D)$ and $P(D/A)$ using the above form formula.

$P(D/A)=\frac{P(A\cap D)}{P(A)}$ ;

$P(A/D)=\frac{P(D\cap A)}{P(D)}$

From the given table, we have the values of P(A), P(D), $P(D\cap A)$ and $P(A\cap D)$ .

Since, Probability= $\frac{The number of wanted outcomes }{the number of possible outcomes}$

∴ $P(A)=\frac{8}{17}$ , $P(D)=\frac{10}{17}$ , $P(A\cap D)=\frac{2}{17}$ and $P(D\cap A)=\frac{2}{17}$

Now, putting these values in above formula we get,

$P(D/A)=\frac{\frac{2}{17}} {\frac{8}{17}}$

$P(D/A)=\frac{2} {8}=\frac{1}{4}$

$P(D/A)= \frac{1}{4}$ .

$P(A/D)=\frac{\frac{2}{17}} {\frac{10}{17}}=\frac{2}{10}$

$P(A/D)=\frac{1}{5}$

As, you can see above that the values of P(A|D) and P(D|A) are not equal.

5 0

3 years ago

Read 2 more answers

How do you do this TwT

tangare [24]

Answer:

Step-by-step explanation:

First step plug the numbers into the equation.

-10/(5+2) = (-10/5) + (-10/2)

Solve both sides of the equation separately.

-10/(5+2) Use distributive property, multiply both 5 and 2 by -10.

= -50 + (-20) = -70

-10/5 + -10/2 Multiply the fractions so they can be added together.

-10/5*2 = -20/10 -10/2*5 = -50/10

-20/10 + -50/10 = -70

Now you have solved both equations and they are both equal to -70, so you have verified that the equations are equal to each other because they both equal -70.

5 0

3 years ago

Find the sum <br> 1/2 (w-6)+ 1/4(w+12)

PolarNik [594]

Answer: 3/4w
Explanation:
1/2(w-6)+1/4(w+12)
= 1/2w-6/3 + 1/4w+12/4
= 1/2w-3 + 1/4w+12/4
= 1/2w +1/4w
= 2/2(1/2)w + 1/4w
= 2/4w+1/4w
=3/4w

5 0

3 years ago

I need help on number six I have graphed the data that is given but I need to find three ordered pairs of numbers for each equat

aliya0001 [1]

x-y=-2
y=x+2

Ordered pairs

(0,2)
(1,3)
(2,4)

And

x-y=2
y=x-2

Ordered pairs

(1,-1)
(2,0)
(-2,-4)

Remember parallel lines have no solutions

8 0

2 years ago

Read 2 more answers