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Verizon [17]
3 years ago
14

PLS HELP For this activity, you can use the audio recorder on your cell phone or a digital camera to record the following sounds

: • the sound of footsteps of someone walking towards you
• the sound of a person starting a car, rewing the engine, and driving away
• the sound of a phone ringing at home as you walk toward it the sound of somebody speaking to you as you walk toward that person
After you record these sounds from different sources, play them back and observe the differences in the recorded sound from each source. Write a note recounting your experience and observations for each of these recordings.​
Computers and Technology
1 answer:
vova2212 [387]3 years ago
8 0

Answer:

So you put down what is recorded. Because every time you Play back the audio it sound's different. When you are doing the Exp. It's Called Sound waves My Friend

Explanation:

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Answer:

Under IEEE 802.1Q, the maximum number of VLANs on a given Ethernet network is 4,094 (4,096 values provided by the 12-bit VID field minus reserved values at each end of the range, 0 and 4,095).

Explanation: found it from google

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Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc
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Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, t_{A} = 100 ps

t_{A} = 150 ps

No. of cycles per instructions,  n_{A} = 2.0

n_{B} = 1.0

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, f_{A} = 2.0 I

CPU clock cycle, f_{B} = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = CPU clock cycle\times clock time

T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps

T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps

Thus B is faster than A

Now,

\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}

\frac{Performance of A}{Performance of B} = \frac{200}{150}

Performance of B is 1.33 times that of A

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If a 60 lb. load is placed on the platform, what will the pressure gauge reading be if the piston area is 5 sq.in? Give your ans
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Answer:

The pressure gauge reading will be;

12 psi

Explanation:

The question relates to relationship of pressure and area

The given parameters for the measurement are;

The weight of the load = 60 lb

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Pressure exerted by a force can be defined as follows;

Pressure =  \dfrac{Force}{Area}

The weight of the load = The force applied by the load

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Pressure =  \dfrac{Force}{Area} = \dfrac{60 \ lb}{5 \ in.^2}  = 12\dfrac{lb}{in.^2} = 12 \ psi

The gauge reading will be 12 psi.

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The internet is considered as Wide Area Network (WAN).

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