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Solnce55 [7]
3 years ago
12

What is an activity that can help you enhance the appearance of your computer’s desktop?

Computers and Technology
2 answers:
aleksandrvk [35]3 years ago
5 0
Depending on your computer, but going to control panel on a Windows computer can change the brightness, and backgrounds. 
PolarNik [594]3 years ago
3 0
Yup, change the background and/or brightnesa
You might be interested in
he timing device in an automobile’s intermittent wiper system is based on an RC time constant and utilizes a 0.500-μF capacitor
Tatiana [17]

Answer:

4000k-ohm to 10,000k-ohm

Explanation:

As we know that time constant for an RC circuit is t=RC

Putting the values of t we can get the range of varaiable resistor as;

t=RC

Putting t=2 we get the first value of the range for the variable resistor

2=R*0.500*10^-6

R=2/(0.500*10^-6)

R=4*10^6

R=4000k-ohm

Now putting t=5 we get the final value for the range of variable resistor

t=RC

5=R*0.500*10^-6

R=5/(0.500*10^-6)

R=10*10^6

R=10,000k-ohm

So variable resistance must be made to vary in the range from 4000k-ohm to 10,000k-ohm

5 0
3 years ago
Use the distributive property to expand the following expression. (9m - 6)7
Nady [450]
(9m - 6)7
(9m × 7) - (6 × 7)
63m - 42
7 0
3 years ago
Read 2 more answers
Sam wants to move across the text and his documents to add data at predefined stops. Which key will Hughes to navigate through t
Setler [38]

Answer:

The TAB key

Explanation:

Sam would use the TAB key, located on the left side of the keyboard, to move around his document to add stops and format its information properly.

Pressing the TAB key will introduce a tab code in his document, which is like moving ahead by a certain number of spaces (5,6, 10 spaces for example, depending on the configuration of the document), but without using spaces, using a tab which is a much better option to position, align things up.

5 0
3 years ago
16.50. Suppose we have a sequential (ordered) file of 100,000 records where each record is 240 bytes. Assume that B = 2,400 byte
Nat2105 [25]

Answer and Explanation:

Given that total number of records in a file = 100000

Each record consists of= 240 bytes

Given that B= 2400 bytes.

Then total blocks in file = 100000 records * 240 / 2400

= 10000 blocks.

Time that will take for exhaustive read

= s + r + b.btt

= 16 + 8.3 + (10000) * 0.8

= 8024.3 msec

Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.

Hence, X (s + r + btt) > 8024.3

X (16+8.3+0.8) > 8024.3

X > 8024.3/25.1

So that, X > 319.69

Hence, atleast 320 random reads should be made to search the file

8 0
3 years ago
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
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