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3 years ago

Select the correct answer from each drop-down menu.

1 answer:

7 0

The two correct terms for nitrate poisoning in newborn infants are BLUE BABY SYNDROME AND METHEMOGLOBINEMIA. ... Presence of high dose of nitrate in the body drastically reduces the amount of oxygen that is found in the blood, this make the color of the baby to become bluish.

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Bob has brown hair and Sally has blonde hair. If brown hair is dominant and blonde hair is recessive, is it possible for Bob and

Dominik [7]

Answer:

no it is not possible

Explanation:

bc when you do a punnett square brown hair is dominant so there is not a possible way for their child to have blonde.

3 0

2 years ago

Read 2 more answers

A science student makes the following statement. A raccoon may live longer when it eats only vegetables. What is the student doi

Elena-2011 [213]

The student is likely engaging or forming a hypothesis in which a hypothesis is a scientific method of having to formulate an intelligent or educated guess that may be an answer as to how a problem has occurred in which the student thinks that the racoon may live longer if it only eats vegetables.

3 0

3 years ago

The primary growth of a plant adds __________, and secondary growth adds __________. View Available Hint(s) The primary growth o

kari74 [83]

Answer:

1. Height

2. Girth

Explanation:

The woody plants grow in two manners: the primary growth and secondary growth.

The primary growth is considered the type of growth which increases the height of the plant which involves the apical meristem present at the tip of the shoot.

When the height increases up to its maximum length, then secondary growth begins which add tissues to the side that is it increases the girth by adding bark, secondary xylem and phloem.

Thus, Height and Girth is correct.

6 0

3 years ago

Read 2 more answers

Please help! Why do plants produce bubbles during photosynthesis? Why is counting them a good way to determine the rate of the p

arlik [135]

Answer:

Bubbles are nothing but the oxygen which arise around the green parts of the plant.

3 0

3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

4 0

2 years ago