All categories

3 years ago

Solve for x 4x+ 14=6x-8

1 answer:

3 0

x=11
x is equal to 11 because you subtract 4x from both sides and then add 8 to both sides where you are left with 2x=22. After dividing by 2, you get x=11

You might be interested in

15 times as much as 1 fifth of 12

Ann [662]

1) Work out what 1/5 of 12 is
To do this, we divide 12 by 5
12/5 = 2.4

2) Multiply 2.4 by 15
2.4 x 15 = 36

If you don't like decimals, you can also do it this way...

This can be rewritten as 15 x 1/5 x 12
Multiplications alone can be performed in any order

1) Work out what 1/5 of 15 is
1/5 of 15
15/5 = 3

2) 3 multiplied by 12
3 x 12 = 36

8 0

3 years ago

Read 2 more answers

Write the slope intercept form Through:(-1,0) and (-5,-5)

jarptica [38.1K]

Answer:

$y=\frac{5}{4} x + \frac{5}{4}$

7 0

3 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

What is angle DCE? A. 34 B. 85 C. 102 D. 98

s2008m [1.1K]

The red line is 180 degrees. So the arcs on top of the circle all equal up to 180 degrees. the number 72 doesn't really matter cause you're trying to find out the angle of DCE which is on the other side of the circle. So you gotta find the arc length of DE which is 68 because 180-112=68. So to find the angle, you have to divide the opposite arc length by two, which is 34.

ANSWER: A. 34. you're welcomee!!

8 0

3 years ago

Read 2 more answers

What is the average rate of change of the function f(x)=20(14)xf(x)=20(14)x from x = 1 to x = 2? Enter your answer, as a decimal

Advocard [28]

The average rate of a function f(x) over an interval x = a and x = b is given by:

$Average \ Rate \ of \ Change= \frac{f(b)-f(a)}{b-a}$

Given the function

$f(x)=20(14)^x$

The average rate of change from x = 1 to x = 2 is given by:

$\frac{f(2)-f(1)}{2-1} = \frac{20(14)^2-20(14)^1}{1} \\ \\ =20(196-14)=20(182)=3,640$

6 0

3 years ago