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BabaBlast [244]
3 years ago
13

The diameter of a truck’s tire is 50 inches. How far down the road will the tire travel if it makes one full turn? (Use 3.14 for

π and round your answer to the nearest inch).
Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

157 inches

Step-by-step explanation:

This question is essentially asking you what the circumference of the wheel is, since after a full turn all of the circle will have touched the road once. The formula for the circumference of a circle is \pi d, where d is the diameter, meaning that the circumference of this tire is 50*3.14=157 inches. Hope this helps!

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ILL GIVE BRAINLIEST IF CORRECT!! The average of x+6, 6x+2, and 2x+7 is 4x-7. What is x?
mina [271]

Answer:

35/3

Step-by-step explanation:

\frac{x+6 + 6x+2+x+6}{3} =4x-7

Simplify to get

9x+14=3(4x-7)

35=3x

x=35/3 or 11.66

6 0
3 years ago
Maria solved the equation below and got x = –4. Which of the following choices verifies that her solution is correct? 5x + 22 =
VladimirAG [237]
5(-4)+22 = (-4)+6
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2 = 2
Maria is correct, since both sides equally match.
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3 years ago
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Novosadov [1.4K]
-12 n - 24 = -12 (n+2) 

-12 (n+2)  is the answer
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A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

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First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

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x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

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\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

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Answer:

Each person gets 2 muffins

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12 divided by 6 is 2

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