Answer:
49 and 58
Step-by-step explanation:
pls brainliest
5(i + 2) = 8(i -1)
5i + 10 = 8i -8
-3i + 10 = -8
-3i = -18
i = 6
Since m + n = 7 we know m = 7-n. So now we have 2n - 3(7-n) = 6. From this we get n = -3. So now we know m - 3 = 7 so m = 10. So now we have 3(-3) + 2(10) = ? and this comes out as 11

Consider, LHS
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We know,

We know,
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So, using this identity, we get

can be rewritten as

<h2>Hence,</h2>


Answer:
I'm pretty sure he or she are right^^
Step-by-step explanation:
I Know