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SpyIntel [72]
2 years ago
6

Help please will give brainliest

Mathematics
1 answer:
alex41 [277]2 years ago
4 0
<h2>Answer:</h2>

<u>Cost of basketball sneakers with tax</u> = $96.12

<u>Amount of tax</u> = 8% of cost price

= 8/100 × 96.12

= $7.6896.

<u>Cost of sneakers without tax</u> = $96.12 - $7.6896.

= $88.43.

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Emily also buys food and toys for her rabbit.She buys a bag of food for 20$.She buys 2 toys for 3$ Each. Write one equation to d
Rina8888 [55]

Answer:

23

Step-by-step explanation:


7 0
3 years ago
A triangular window is above the door to a cafe. The base of the window is 12 ft, and the height is 10 ft. What is the area of t
Digiron [165]
The area of the triangle is 60. 
12 x 10 = 120 
120/2 = 60
3 0
3 years ago
Read 2 more answers
the area of a rectangle is 14 square units. it has side lengths a and b. If a= 2 1/3, what is the value of b
Zolol [24]

Step-by-step explanation:

subtrat 14 and 2 1/3 to get b

5 0
3 years ago
What is the value of b?
anzhelika [568]
The value of b is 24

Since b + 24 and 2b are equal to each other the equation will be this :

B + 24 = 2b
You will subtract b on both sides
24 = b
This is the answer
3 0
2 years ago
Which is the simplified form of (9c^-9)^-3?
ElenaW [278]

Answer:

We conclude that:

\left(9c^{-9}\right)^{-3}=\frac{c^{27}}{729}

Step-by-step explanation:

Given the expression

\left(9c^{-9}\right)^{-3}

Apply exponent rule:   a^{-b}=\frac{1}{a^b}

\left(9c^{-9}\right)^{-3}=\frac{1}{\left(9c^{-9}\right)^3}

Let us first solve:

\left(9c^{-9}\right)^3

Apply exponent rule:  \left(a\cdot \:b\right)^n=a^nb^n

\left(9c^{-9}\right)^3=9^3\left(c^{-9}\right)^3

             =729\left(c^{-9}\right)^3

Apply exponent rule:   \left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

             =729c^{-9\cdot \:3}

             =729c^{-27}

Apply exponent rule:   a^{-b}=\frac{1}{a^b}

             =729\cdot \frac{1}{c^{27}}

             =\frac{729}{c^{27}}

Therefore, the expression \left(9c^{-9}\right)^{-3}=\frac{1}{\left(9c^{-9}\right)^3} becomes

\left(9c^{-9}\right)^{-3}=\frac{1}{\left(9c^{-9}\right)^3}

               =\frac{1}{\frac{729}{c^{27}}}         ∵  \left(9c^{-9}\right)^3=\frac{729}{c^{27}}

               =\frac{c^{27}}{729}          ∵  \frac{1}{\frac{b}{c}}=\frac{c}{b}

Hence, we conclude that:

\left(9c^{-9}\right)^{-3}=\frac{c^{27}}{729}

3 0
3 years ago
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