You can write it in the form a^2 - b^2 where a = 5x and b = p
(5x)^2 - p^2
And then use the Difference of Squares a^2 - b^2 = (a + b)(a - b)
Answer is (5x + p)(5x - p)
By definition, the perimeter of the triangle is the sum of its sides.
We must then use the formula of distance between points:

We now look for the longitus for each of the sides:
For L1:

For L2:

For L3:
Then, the perimeter is given by:
P = L1 + L2 + L3
Substituting values we have:
Answer:
the perimeter of triangle ABC is:
none of the above.
Answer:
1 is neither prime nor a composite number because it only has 1 divisor, 1 and 1, and it doesn't have more than 2 integral divisors, like stated, it only has 1. So it falls in neither category.
You will need to work left to right.
p - 10p + -5p +14p - -9p - 2 = -20
-9p + -5p +14p - -9p - 2 = -20
-14p +14p - -9p - 2 = -20
0p- -9p - 2 = -20
9p - 2 = -20
Then you will want to eliminate 2 by adding it to both sides
9p = -18
Then divide by 9 to isolate P
p=-2
3/5 + 5/7 = 1 11/35 - 1/5 = 1 4/35 which is your final answer.