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Savatey [412]
3 years ago
6

A package of organic strawberries costs $1.50 while they are in season and $2.25 when they aren't in season. What is the percent

increase?
Mathematics
2 answers:
andre [41]3 years ago
4 0
I wanna say 6 percent if you divide
Brut [27]3 years ago
4 0

Answer:

50% increase.

Step-by-step explanation:

It is given that A package of organic strawberries costs $1.50 while they are in season and $2.25 when they aren't in season.

Price when in season = 1.50

Price when not in season = 2.25

The difference in the price = 0.75

For 1.50 increase = 0.75

Therefore, \frac{0.75}{1.50} × 100

= 50

So answer is organic strawberries cost increase by 50% while they are not in season.

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OlgaM077 [116]

Find the time it will take:

195 miles / 50 miles per hour = 3.9 hours.

1 hour = 60 minutes:

0.9 hours x 60 = 54 minutes.

3.9 hours = 3 hours and 54 minutes.

Add 3 hours and 54 minutes to the time it leaves:

3:30 pm + 3 hours = 6:30 PM

6:30 + 54 minutes = 7:24 PM

8 0
3 years ago
Which pair of monomials has the least common multiple (LCM) of 54x2y3?
Lera25 [3.4K]

ANSWER

The correct answer is D.

EXPLANATION

If we express the monomial,

18 {x}^{2} y

as product of primes, we obtain:

2 \times  {3}^{2}  \times  {x}^{2}y

If we express the monomial

27x {y}^{3}

as product of primes we obtain:

=  {3}^{3}  \times x {y}^{3}

The least common multiple of these two binomials is the product of the highest powers of the common factors.

The LCM is

= 2 \times  {3}^{3}  \times  {x}^{2} {y}^{3}

=54 {x}^{2} {y}^{3}

Therefore the correct answer is D.

6 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP!! I NEED TO GET THIS RIGHT
satela [25.4K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Help me graph<br><br> y=3-|x-1|
nexus9112 [7]

Answer:

In the photo below.

6 0
3 years ago
If x square plus 8x plus q =(x plus k) Square find the value of k and q​
PIT_PIT [208]

Answer:

The value of k is 4 and q is 16.

Step-by-step explanation:

First, you have to expand the brackets by applying :

{(a + b)}^{2}  =  {a}^{2}  + 2ab +  {b}^{2}

{x}^{2}  + 8x + q =  {(x + k)}^{2}

{x}^{2}  + 8x + q =  {x}^{2}  + 2kx +  {k}^{2}

Next, you have to do it by comparison :

{x}^{2}  + 8x + q =  {x}^{2}  + 2kx +  {k}^{2}

by \: comparison

8x = 2kx

8 = 2k

k = 4

q =  {k}^{2}

q =  {4}^{2}

q = 16

7 0
3 years ago
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