To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
All real numbers greater than or equal to 1
Answer:
x = 17 and y = 37
Step-by-step explanation:
Let the numbers be x and y.
y = 3 + 2x
xy = 629
substituting y in the second equation we get
x(3+2x) = 629
3x + 2
= 629
2 + 3x - 629 = 0
Solving a quadratic equation by using its formula:
x = [-3 ±√(9-4(2)(-629)] / 4
x = [-3 ± √5041] / 4
x = [-3 ± 71] / 4
x = 17 and 
Ignore the negative number in x and just use x = 17 in the first equation we get
y = 3 + 2(17) = 37
Answer:
sorry my brian aint working
Step-by-step explanation:
