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klio [65]
3 years ago
15

the students on a decorating committee create a banner. The length of the banner is 2.5 times its width. The length of the banne

r is 20 feet. What is the width (in feet) of the banner
Mathematics
2 answers:
finlep [7]3 years ago
5 0

Answer:  8 feet.

Step-by-step explanation:

Given : The students on a decorating committee create a banner.

Let x be the width of the banner.

The length of the banner is 20 feet.

The length of the banner is 2.5 times its width.

Then, we have

2.5x=20

Divide both the sides  by 2.5 , we get

x=\dfrac{20}{2.5}=8

Therefore,  the width (in feet) of the banner= 8 feet.

Lilit [14]3 years ago
4 0

The width is 8 feet

20 divided by 2.5 equals 8 feet

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The store salsa jars have a height of ten centimeters and a radius of five centimeters. If
Alex_Xolod [135]

Answer:

471.2 cm³ missing

Step-by-step explanation:

jars are cylinders

volume of cylinder = π * r² * h

h=10

r=5

v=785.4 cm³ of a full jar

r stays the same = 5

h = 4

v= 314.2 cm³ left in the jar

whats missing is the full-left

785.4-314.2=471.2 cm³ missing

6 0
3 years ago
200 at 6% twice a year how much will Rachel have in ten years
Svetach [21]
A=P(1+R)^n
A=amount in 10 years
P=original amount (200)
R=rate(o.o6)
n=number of times compunded(20)
A=200x1.06^20
  =641.4270944
Therefore Rachel will have 641.42 in 10 years
6 0
2 years ago
Quotient of 0.72 / 4
sasho [114]

Answer: The answer is 0.18

Step-by-step explanation:

I took the test

5 0
2 years ago
Nick has tennis practice every sixth day. Mark has tennis practice every 4th day. On July 31st they both had tennis practice. Wh
Montano1993 [528]

Nick has tennis practice every sixth day = 6

Mark has tennis practice every 4th day = 4

They both had tennis practice on = 31st July

We have to find when will be the next time that they both have practice on the same day?

For this, we will find the LCM of 4 and 6

So, LCM of 4 and 6 is 12.

So, it will be 12 days after 31st July, that they will practice on the same day.

So it is 12th August.


3 0
3 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
3 years ago
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