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3 years ago

I need help with this question

Mathematics

1 answer:

Rudiy273 years ago

8 0

Since the angle is positive, you can find any coterminal angle by applying:

Angle + x = 2π ==> 7π/6 + x = 2π ==> x = 2π - 7π/6

x= 12π/6 -7π/6 = 5π/6

So the angle 5π/6 is the coterminal of 7π/6

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6 + ( 2 − 3 ( 4 ) ) + 1 /( 5 ) ( 2 ) − 4

tankabanditka [31]

6 + (2 - 3 (4) )+1 / (5) (2) - 4 = -1 /2

<u>Step-by-step explanation:</u>

6 + (2 - 3 (4) )+1 / (5) (2) - 4

Using the BODMAS rule, we can simplify the expression in the following way, like, we have to do the operation inside the brackets first, then division, multiplication, addition and then subtraction.

= 6 + (2 - 3 (4) )+1 / (5) (2) - 4 [operation inside the brackets]

= 6 + (2 - 12) )+1 / (5) (2) - 4

= 6 + (-10) )+1 / (10) - 4

= 6 + 1 -10 / (10) - 4

= 7 - 10/ 6

= -3 / 6

= -1/2

4 0

3 years ago

Are ac and be congruent explain?

anzhelika [568]

AC is a line with length of 7 units, from -7 to 0

BE is a line with length of 6 units, from 0 to 6

Two shapes are congruent if their length are the same, hence AC and BE is not congruent

4 0

3 years ago

Please do this math for me or else i will steal your cookies

kompoz [17]

Answer:

Step-by-step explanation:

$-7x+16=58\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\-7x+16-16=58-16\\\\-7x=42\\\\\mathrm{Divide\:both\:sides\:by\:}-7\\\\\frac{-7x}{-7}=\frac{42}{-7}\\\\x =-6$

$-2x+15=-9\\\\\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}\\\\-2x+15-15=-9-15\\\\-2x=-24\\\\\mathrm{Divide\:both\:sides\:by\:}-2\\\\\frac{-2x}{-2}=\frac{-24}{-2}\\\\x=12\\$

$5x-4=36\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\5x-4+4=36+4\\\\5x=40\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}=\frac{40}{5}\\\\x=8$

$25-3x=88\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\\\25-3x-25=88-25\\\\\mathrm{Divide\:both\:sides\:by\:}-3\\\\\frac{-3x}{-3}=\frac{63}{-3}\\\\x=-21$

$-11=7-x\\\\\mathrm{Add\:}x\mathrm{\:to\:both\:sides}\\\\-11+x=7-x+x\\\\-11+x=7\\\\\mathrm{Add\:}11\mathrm{\:to\:both\:sides}\\\\-11+x+11=7+11\\\\x=18$

$65+15x=35\\\\\mathrm{Subtract\:}65\mathrm{\:from\:both\:sides}\\\\65+15x-65=35-65\\\\\mathrm{Divide\:both\:sides\:by\:}15\\\\\frac{15x}{15}=\frac{-30}{15}\\\\x=-2$

$\frac{1}{2} x-18=2\\\\\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\\\\frac{1}{2}x-18+18=2+18\\\\\frac{1}{2}x=20\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\\\2\times\frac{1}{2}x=20\times \:2\\\\x=4$

$\frac{2}{3}x-10=-12 \\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{2}{3}x-10+10=-12+10\\\\\frac{2}{3}x=-2\\\\Divide\:both\:sides\:by\: 2/3\\\\\frac{2}{3}x\div \frac{2}{3} =-2\div \frac{2}{3} \\\\\frac{2}{3} x\times \frac{3}{2} =-2\times\frac{3}{2} \\\\x =-3$

$6-\frac{1}{3}x=-1 \\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-\frac{1}{3}x-6=-1-6\\\\-\frac{1}{3}x=-7\\\\\mathrm{Multiply\:both\:sides\:by\:}-3\\\\\left(-\frac{1}{3}x\right)\left(-3\right)=\left(-7\right)\left(-3\right)\\\\x=21$

10.

$4-9x=-14\\\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\\\4-9x-4=-14-4\\\\-9x=-18\\\\\mathrm{Divide\:both\:sides\:by\:}-9\\\\\frac{-9x}{-9}=\frac{-18}{-9}\\\\x=2$

11.

$11-x=29\\\\\mathrm{Subtract\:}11\mathrm{\:from\:both\:sides}\\\\-x=18\\\\\mathrm{Divide\:both\:sides\:by\:}-1\\\\\frac{-x}{-1}=\frac{18}{-1}\\\\x=-18$

12.

$-9-11x=68\\\\\mathrm{Add\:}9\mathrm{\:to\:both\:sides}\\\\-9-11x+9=68+9\\\\-11x=77\\\\\mathrm{Divide\:both\:sides\:by\:}-11\\\\\frac{-11x}{-11}=\frac{77}{-11}\\\\x=-7$

13.

$45+\frac{5}{6}x =50\\\\\mathrm{Subtract\:}45\mathrm{\:from\:both\:sides}\\\\45+\frac{5}{6}x-45=50-45\\\\\frac{5}{6}x=5\\\\\mathrm{Divide\:both\:sides\:by\:}5/6\\\\\frac{5}{6} x\div\frac{5}{6}=5\div\frac{5}{6}\\\\\frac{5}{6}x\times \frac{6}{5}= 5\times\frac{6}{5}\\\\ x=6$

14.

$-5x+17=-33\\\\\mathrm{Subtract\:}17\mathrm{\:from\:both\:sides}\\\\-5x+17-17=-33-17\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\\\frac{-5x}{-5}=\frac{-50}{-5}\\\\x=10$

15.

$95=-4+33x\\\\-4+33x=95\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\-4+33x+4=95+4\\\\\mathrm{Divide\:both\:sides\:by\:}33\\\\\frac{33x}{33}=\frac{99}{33}\\\\x=3$

3 0

3 years ago

Evaluate the expression 2m+2n if m=9 and n=3

tatuchka [14]

Just substitute each number in for the variables: 9 for m and 3 for n.

2m+2n
= 2(9)+2(3)
= 18+6
= 24

4 0

3 years ago

Read 2 more answers

Which equation represents a line parallel to 3x-8y=12?

TEA [102]

Answer:

B. y = -3/8x - 4

Step-by-step explanation:

Given equation: 3x - 8y = 12

Find a parallel line that matches one of the equations shown.

First, find the slope by solving for y:

3x - 8y = 12

8y = -3x + 12

y = -3/8x + 12/8

y = -3/8x + 3/2

Slope m = -3/8

Since the slope of a line parallel is the same slope, the only equation that fits the conditions is B because in the form y = mx + b, m = -3/8

5 0

3 years ago