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tekilochka [14]
2 years ago
8

If anyone knows how to code on python:

Computers and Technology
1 answer:
Allushta [10]2 years ago
5 0

Answer:

def dice_roller():

   # ask for first input

   input1 = int(input("Enter the first roll: "))

   # check if it's valid

   while input1 < 1 or input1 > 6:

       print("Invalid number")

       # ask for new input if the previous was invalid

       input1 = int(input("Enter the first roll: "))

   # ask for second input

   input2 = int(input("Enter the second roll: "))

   # check if it's valid

   while input2 < 1 or input2 > 6:

       print("Invalid number")

       # ask for new input if the previous was invalid

       input2 = int(input("Enter the second roll: "))

   # check of the numbers are the same

   if input1 == input2:

       print("You rolled the same numbers. Try again")

       # if they are the same call this function again to get new numbers

       dice_roller()

   else:

       # print how many spaces to advance

       print("Advance", input1+input2, "spaces")

if __name__ == '__main__':

   dice_roller()

Download txt
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Which statement accurately describes DTP programs?
s2008m [1.1K]

Answer:

O DTP programs are basically layout programs.

Explanation:

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3 years ago
The technology dealing with robots is called
Alisiya [41]
<h2> Robotics </h2>

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3 years ago
Windows uses a memory-management technique known as ________ to monitor which applications you use most frequently and then prel
lukranit [14]

Answer:

SuperFetch

Explanation:

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3 years ago
In java write a program:A contact list is a place where you can store a specific contact with other associated information such
BigorU [14]

Answer:

import java.util.Scanner;

public class ContactInformation

{

public static String GetPhoneNumber(String[] nameVec, String[] phoneNumberVec, String contactName, int arraySize)  

{  

for(int i=0;i<arraySize;i++)

{

if(nameVec[i].equals(contactName))  

return phoneNumberVec[i];

}  

return "Contact doesn't exists!";

}

public static void main(String[] args)

{

int records;

Scanner sc = new Scanner(System.in);

System.out.print("Enter the size of contact List :");

records=sc.nextInt();

String[] contactNameList=new String[records];

String[] phoneNumberList=new String[records];

String contactName;

System.out.println("Enter the contact name and phone number :");

for(int i=0;i<contactNameList.length;i++)

{  

contactNameList[i]=sc.next();  

phoneNumberList[i]=sc.next();  

}  

System.out.println("Enter the name of the contact to be searched :");  

contactName=sc.next();

System.out.println(GetPhoneNumber(contactNameList,phoneNumberList,contactName,records));  

}  

}

Explanation:

In the following the function defined above for getting the contact

number on the basis of contact number provided we are checking the contact name list if we are able to find the contact name and if we did we return the contact number on the same index from the contact number list

which we found in the contact name list.

4 0
3 years ago
JAVA
butalik [34]

Answer:

import java.util.*;

public class MyClass {

   public static void main(String args[]) {

       Scanner input = new Scanner(System.in);

       System.out.print("Input a word: ");

       String userinput = input.nextLine();

       for(int i =0;i<userinput.length();i+=2) {

           System.out.print(userinput.charAt(i));

       }

   }

}

Explanation:

This line prompts user for input

       System.out.print("Input a word: ");

This declares a string variable named userinput and also gets input from the user

       String userinput = input.nextLine();

The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2

       for(int i =0;i<userinput.length();i+=2) {

This prints characters at i-th position

           System.out.print(userinput.charAt(i));

5 0
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