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tensa zangetsu [6.8K]

3 years ago

14

Brainliest FREEE................................................................................................................

........................

2 answers:

zheka24 [161]3 years ago

7 0

Answer:

hi thx bye

Step-by-step explanation:

Ivanshal [37]3 years ago

3 0

Ywssssss meeeee pleaaeeeee

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The last time he checked, Matthew was 40 inches tall. Matthew just measured himself again and found out that he is 10% taller no

weqwewe [10]

44 inches.

All you have to do is find out what 10% of 40 is then add it back to 40. In the case of finding 10% of something you just “chop” of the back number (or move the decimal place forward) so 10% of 40 is 4. The. 40+4=44.

You can also multiply fractions to find the percent of a number but that is not necessary in this case.

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3 years ago

Substitute the value n = 4 in the expressions<br><br>2n<br>n + 2<br>3(n+4)

Lelu [443]

Step-by-step explanation:

Given n = 4

2n = 2* 4= 8

n + 2 = 4 + 2 = 6

3(n + 4) = 3( 4 + 4) = 3 * 8 = 24

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2 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

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