For the first one
x=-6
the second your answer is 2.92 hours
-7/2 and -1/2 (there both fractions)
Cot²x/csc+1
=(csc²x-1)/(csc+1)
=((1/sin²x)-1)/((1/sinx)+1)
=((1-sin²x)/sin²x)/((1+sinx)/sinx)
=(1-sin²x)/(1+sinx)
=(1+sinx)(1-sinx)/sinx(1+sinx)
=(1-sinx)/sinx
Answer:
95%
Step-by-step explanation:
The z-scores associated with the limits are ...
z = (x -μ)/σ
z = ({80, 108} -94)/7 = {-14, 14}/7 = {-2, 2}
That is, we're interested in flight times that lie within 2 standard deviations of the mean. The empirical rule tells us that 95% of the distribution lies within 2 standard deviations of the mean.
Answer:
b=14
Step-by-step explanation:
Add 4b and 8b, which you get 12b. Then you add 11 and 1 which you get 12.
12b + 12 = 180 is the next equation.
Afterwards, you subtract 12 from 180.
12b = 168
Divide 12b from 168.
b = 14