Question

Consider the derivation of the quadratic formula below. What is the missing radicand

Answer 1

Answer:

$\frac{b^2 - 4ac}{4a^2}$

Step-by-step explanation:

Given

See attachment for complete question

Required:

Complete step 6

At step 5, we have:

$(x + \frac{b}{2a})^2 = \frac{b^2}{4a^2} - \frac{4ac}{4a^2}$

Take LCM

$(x + \frac{b}{2a})^2 = \frac{b^2 - 4ac}{4a^2}$

Take square roots of both sides to get step 6

$x + \frac{b}{2a} = \±\sqrt{\frac{b^2 - 4ac}{4a^2}}$

Hence, the missing radicand is: $\frac{b^2 - 4ac}{4a^2}$