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3 years ago

What is the inverse function of f(x)=6x^3-3?

1 answer:

7 0

f(x)=6x^3-3

1. Replace f(x) with y: y = 6x^3 - 3
2. Interchange x and y: x = 6y^3 - 3 x+3 x+3
3. Solve this result for y: y^3 = --------- or y = cube root of -------
-1 6 6
4. Replace y with f (x)

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Suppose you have 60 kg of a radioactive material that decays 50% of its mass every year how much material would you have left af

bogdanovich [222]

Answer:

Step-by-step explanation:

60 kg × 0.5⁴ = 3.75 kg

It doesn’t match any of the answers

4 0

3 years ago

Is 5 a solution to -3x=15

viva [34]

Answer:

Step-by-step explanation:

Step 1: Set x to 5 and check

$-3x = 15$

$-3(5) = 15$

$-15 \neq 15$

So... 5 is not a solution

Answer: No

3 0

3 years ago

Read 2 more answers

For each of the following questions, if there is more than one solution, enter all solutions as a comma-separated list (like "1,

PtichkaEL [24]

Answer:

Vertical intercept at y=43

Horizontal intercept at x= $-\frac{43}{6}$

Step-by-step explanation:

We are given that a function

$f(x)=6(x+8)-5$

We have to find the vertical intercept and horizontal intercept.

Vertical intercept : It is defined as the value of y for which x is equal to zero.

Horizontal intercept: It is defined as the value of x for which y is equal to zero.

Let y= $f(x)=6(x+8)-5$

Substitute x=0

$y=6(8)-5$

$y=43$

Therefore, vertical intercept at y=43

Substitute y=0

$0=6(x+8)-5$

$6x+48=5$

$6x=5-48=-43$

$x=\frac{-43}{6}$

Horizontal intercept at x= $-\frac{43}{6}$

3 0

3 years ago

Directions- Find the indicated term of each arithmetic sequence.

____ [38]

Answer:

1. 98.8 2. 194 3. 49 2/3

Step-by-step explanation:

I found the pattern of each of them

Here is the math I did for the 1st one: 1.3(1st number)+2.5*39(pattern times one less than the term number you want)=98.8

This is actually the first time I have done this, so I this should help both of us!!! Me with learning more math, and you with doing your own math.

4 0

3 years ago

Without solving determine the number of real solutions for each quadratic equation

seropon [69]

Answer:

b^2-4b+3=0

b²-3x-b+3=0

b(b-3)-1(b-3)=0

(b-3)(b-1)=0

either

b=3 or b=1

2n^2 + 7 = -4n + 5

2n²+4n+7-5=0

2n²+4n+2=0

2(n²+2n+1)=0

(n+1)²=0/2

:.n=-1

x - 3x^2 = 5+ 2x - x^2

0=5+ 2x - x^2-x +3x^2

0=5+x+2x²

2x²+x+5=0

comparing above equation with ax²+bx +c we get

a=2

b=1

c=5

x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1

={-1±√-39}/2

3 0

3 years ago