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weeeeeb [17]
3 years ago
10

What is the inverse function of f(x)=6x^3-3?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0
<span>f(x)=6x^3-3

1.  Replace f(x) with y:  y = 6x^3 - 3   
2.  Interchange x and y:  x = 6y^3 - 3       x+3                                      x+3
3.  Solve this result for y:    y^3 =           ---------   or y = cube root of  -------
                                 -1                                6                                          6
4.  Replace y with  f     (x)

</span>
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Step-by-step explanation:

<h2><u>HELP KEY FOR SLOPE RIGHT HERE!</u></h2>

Using the Slope Equation:

Pick two points on the line and determine their coordinates.

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Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

How do you calculate rise over run?

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What does a slope of mean?

The slope of a line is the steepness of the line. There are many ways to think about slope. Slope is the rise over the run, the change in 'y' over the change in 'x', or the gradient of a line.

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the length of a rectangle is 50 feet less than its width. If the perimeter of the field is 840 feet, find the length of the fiel
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8 0
2 years ago
If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

7 0
3 years ago
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