Triangles ABC and LBM are similar. We know this because AL and LB have the same length, so that AB is twice as long as either AL or LB. The same goes for MC and BM, and BC. The angle B is the same for both tirangles ABC and LBM, so the side-angle-side postulate tells us the triangles are similar, and in particular that triangle ABC is twice as large as LBM.
All this to say that LM must be half as long as AC, so LM has length (B) 14 cm.
Answer:
The answer to your question is (3, 0)
Step-by-step explanation:
Data
4x + 2y = 12 Equation l
x - y = 3 Equation ll
Process
To solve this problem use the elimination method
1.- Multiply equation ll by 2
4x + 2y = 12
2x - 2y = 6
6x 0 = 18
2.- Solve for x
6x = 18
x = 18/6
x = 3
3.- Substitute x in equation ll to find y
3 - y = 3
-Solve for y
-y = 3 - 3
y = 0
4.- Write the solution
(3, 0)
Answer:
28/6 yeah thats right wasp
I don't know really ask someone smarter than me
Answer:
∠AEC = 139°
Step-by-step explanation:
Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle
Substitute values into the equation
11x - 12 + 4x + 1 + 4x + 1 = 180, that is
19x - 10 = 180 ( add 10 to both sides )
19x = 190 ( divide both sides by 19 )
x = 10
Hence
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence
∠AEC = (15 × 10) - 11 = 150 - 11 = 139°