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GREYUIT [131]
3 years ago
12

Evaluate each expression. Click on undefined as needed

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0
If the 0 is in the numerator, the value is 0
if the 0 is in the denominator, the value is undefined

so 0/8 = 0
and 3/0 = undefined

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Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 1818 cans of the
ohaa [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 18 cans of the soda drink. Those volumes have a mean of 12.19 oz and a standard deviation of 0.14 oz, and they appear to be from a normally distributed population.

If the workers want the filling process to work so that almost all cans have volumes between 12.02 oz and 12.66 ​oz, the range rule of thumb can be used to estimate that the standard deviation should be less than 0.16 oz. Use the sample data to test the claim that the population of volumes has a standard deviation less than 0.16 oz. Use a 0.01 significance level. Complete parts​ (a) through​ (d) below.

a. Identify the null and alternative hypotheses.  

b. Compute the test statistic.

c. Find the p-value.

d. State the conclusion.

Answer:

Null hypotheses = H₀: σ = 0.16  oz

Alternate hypotheses = H₁: σ < 0.16  oz

Critical value = 6.408

Chi-square value = \chi^2 = 13.016

Reject H₀  Since \chi^2 > Critical value

Reject H₀ Since p-value ≤ α

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

Step-by-step explanation:

Set up hypotheses:

The null hypotheses is that the population of volumes has a standard deviation of 0.16 oz

Null hypotheses = H₀: σ = 0.16  oz

The claim to be tested is that the population of volumes has a standard deviation of less than 0.16 oz

Alternate hypotheses = H₁: σ < 0.16  oz

Determine type of test:

Since the alternate hypothesis states that the population of volumes has a standard deviation of less than 0.16 oz, therefore we will use a lower-tailed chi-square test.

Determine the Critical value:

Given level of significance = 0.01

Since it is a lower-tailed test, the areas given in the chi-square table are the areas to the right of the critical value. To get the areas on the left, subtract it from  one, and then look it up

α = 1 - 0.01 = 0.99

degree of freedom = df = n - 1 = 18 - 1 = 17

The critical value from the chi-square table at α = 0.99 and df = 17 is found to be

Critical value = 6.408

Using an online “chi-square p-value calculator”

The left tail p-value for df = 17 and Critical value = 6.408 is found to be

p-value = 0.01

Set up decision rule:

Reject H₀ If  > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

OR

Reject H₀ If p-value ≤ α

Compute the test statistic:

$ \chi^2 = \frac{(n-1) s^2}{\sigma^2} } $

$ \chi^2 = \frac{(18-1) 0.14^2}{0.16^2} } $

\chi^2 = 13.016

Conclusion:

We reject H₀

Since \chi^2 > Critical value

13.016 > 6.408

Also

p-value ≤ α

0.01 ≤ 0.01

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

5 0
2 years ago
2 f(x)=x2 + 2x cómo se evalúa?<br><br>a) f(3)<br>b) f(-1)<br>c) f(x-3)​
abruzzese [7]

Answer:

b) f (-1) ese es el resultado

5 0
2 years ago
A high school will only offer a pottery class next year if at least 15 students sign up. So far, 9
andrey2020 [161]
9 + x > (equal to or greater than) 15
6 more students need to sign up because 15-9=6
3 0
2 years ago
If the area of a circle measures 25 pi cm², what is the circumference of the circle in terms of pi?
jeyben [28]

Answer:

10π cm

Step-by-step explanation:

Given

Area of the circle=25π cm^2

Solution

πr^2=25π

r^2=25

r=√25

r=5

So circumference of the circle=2πr

=2π×5

=10π cm

So the answer is 10π cm

8 0
2 years ago
In a class of 35 students, 14 are male. what percent of the class is male?
mars1129 [50]
Total number of students = 35

Number of male students = 14

% of students that are male = \frac{14}{35} * 100 =  \frac{14}{7} * 20 = 2 * 20 = 40 %
8 0
3 years ago
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