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Nimfa-mama [501]
2 years ago
14

The figure below is a square pyramid where the height of the pyramid is 2 centimeters and the volume is 24 cubic centimeters. If

the volume of a pyramid is , then what is the length of the base?
2 centimeters
4 centimeters
8 centimeters
6 centimeters
Mathematics
1 answer:
Murrr4er [49]2 years ago
4 0

Answer:

HIIIIIIII NMMNDKK F.

Step-by-step explanation:

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Pls 24 n 3-4 am not understanding them can u solve them pls
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One car travels 45 mph and the other one travels 52 mph if they start from the same place at the same time traveling in the same
Alinara [238K]

Answer:

the faster car will be 7 miles ahead the slower car

Step-by-step explanation:

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3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

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(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

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3 years ago
The difference of r and 3 (what is an algebraic expression for the word phrase)
Juli2301 [7.4K]
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Read 2 more answers
sofia has to walk 1 2/25 miles to school. she has already walk 2/3 of a mile. how much farther dose she need to walk ? help me p
love history [14]

Answer:

She need to walk 31/75 miles to school.

Step-by-step explanation:

It is given that,

Sofia has walk 1\dfrac{2}{25} miles to school. She has already walk \dfrac{2}{3} of a mile.

We need to find how much farther does she need to walk.

Total distance =  1\dfrac{2}{25} =\dfrac{27}{25}

Let she has to walk x distance to school.

x=\dfrac{27}{25}-\dfrac{2}{3}\\\\=\dfrac{31}{75}

Hence, she need to walk 31/75 miles to school.

7 0
3 years ago
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