<h2>
Area of rectangle is 10L-L²</h2>
Step-by-step explanation:
Let L be the length and W be the width.
Perimeter of rectangle = 2 ( L + W )
That is
2 ( L + W ) = 20
L + W = 10
W = 10 - L
We need to express the area of the rectangle as a function of the length of one of its sides.
Area = Length x Width
A = LW
A = L(10 - L) = 10L-L²
Area of rectangle is 10L-L²
7-3y=22
-7 -7
-3y=15
Divide by -3. y=-5
Answer:
23
Step-by-step explanation: You have to do 5x5 because 5^2 mans there is two fives. Then you just subtract two
5x5=25
25-2=23
Answer:
Option D is right,.
Step-by-step explanation:
-a+4b+2c=-8 ... i
3a+b-4c=9 ... ii
b=-1 ... iii
Substitute the value of b, in i and ii
-a-4+2c =-8 or -a+2c = -4
and 3a-1-4c = 9 or 3a -4c =8
Now we have two equations in two variables
-a+2c =-4 and 3a-4c =8
a = 2c+4: substitute this in the other equatin.
3(2c+4)-4c =8 Or 2c +12 =8
2c =-4 or c = -2
Substitute in -a+2c =12
-a-2 = -4
a = -2+4 =2
a=2, b=-1 and c =-1 is the solution.
Answer:
3) (x-5)^2+y^2=36
Step-by-step explanation:
